### Problem Statement6. A car starts from rest and accelerates at a rate of 1.8 m/s² West for 15 s. It goes at a constant velocity for 50 s and then accelerates at a rate of 2.1 m/s² East for 10 s. Use West as the positive direction.#### Tasks:a. Draw an acceleration graph for this situation. Remember to quantitatively label your axes.b. What is the change in velocity for each time interval?| t (s) | Δv (m/s) ||-------|----------|| 0-15 | || 15-65 | || 65-75 | |c. Draw a velocity graph for this situation. Remember to quantitatively label your axes.d. What is the total displacement between t=0 s and t=75 s?### Description of GraphsFor part (a), you need to plot an acceleration vs. time graph. The x-axis represents time (t) in seconds, and the y-axis represents acceleration (a) in m/s². You need to mark:- From 0 to 15 seconds, acceleration is 1.8 m/s² (positive direction, West).- From 15 to 65 seconds, acceleration is 0 m/s² (constant velocity).- From 65 to 75 seconds, acceleration is -2.1 m/s² (negative because it is East, opposite to the initial direction).For part (b), calculate the change in velocity (Δv) using the formula:\[ \Delta v = a \cdot t \]- From 0 to 15 seconds, \(\Delta v = 1.8 \times 15 = 27 \) m/s.- From 15 to 65 seconds, \(\Delta v = 0 \) m/s.- From 65 to 75 seconds, \(\Delta v = -2.1 \times 10 = -21 \) m/s.For part (c), you need to plot a velocity vs. time graph. The x-axis represents time in seconds, and the y-axis shows velocity in m/s. You should include:- From 0 to 15 seconds, velocity increases from 0 to 27 m/s.- From 15 to 65 seconds, velocity remains constant at 27 m/s.- From 65

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A car starts from rest and accelerates at a rate of 1.8 m/s² West for 15s. It goes at a constant velocity for 50s and then accelerates at a rate of 2.1m/s² East for 10 s. Use West as the positive direction. a. Draw an acceleration graph for this situation. Remember to quantitatively label your axes.

A car starts from rest and accelerates at a rate of 1.8 m/s² West for 15s. It goes at a constant velocity for 50s and then accelerates at a rate of 2.1m/s² East for 10 s. Use West as the positive direction. a. Draw an acceleration graph for this situation. Remember to quantitatively label your axes.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Units and Dimensions

These are generally defined as the terms which precede or describes the dimensions further. These are also further divided into two parts namely fundamental units and the derived units.

Question

### Problem Statement

6. A car starts from rest and accelerates at a rate of 1.8 m/s² West for 15 s. It goes at a constant velocity for 50 s and then accelerates at a rate of 2.1 m/s² East for 10 s. Use West as the positive direction.

#### Tasks:

a. Draw an acceleration graph for this situation. Remember to quantitatively label your axes.

b. What is the change in velocity for each time interval?

| t (s) | Δv (m/s) |
|-------|----------|
| 0-15 | |
| 15-65 | |
| 65-75 | |

c. Draw a velocity graph for this situation. Remember to quantitatively label your axes.

d. What is the total displacement between t=0 s and t=75 s?

### Description of Graphs

For part (a), you need to plot an acceleration vs. time graph. The x-axis represents time (t) in seconds, and the y-axis represents acceleration (a) in m/s². You need to mark:

- From 0 to 15 seconds, acceleration is 1.8 m/s² (positive direction, West).
- From 15 to 65 seconds, acceleration is 0 m/s² (constant velocity).
- From 65 to 75 seconds, acceleration is -2.1 m/s² (negative because it is East, opposite to the initial direction).

For part (b), calculate the change in velocity (Δv) using the formula:

\[ \Delta v = a \cdot t \]

- From 0 to 15 seconds, \(\Delta v = 1.8 \times 15 = 27 \) m/s.
- From 15 to 65 seconds, \(\Delta v = 0 \) m/s.
- From 65 to 75 seconds, \(\Delta v = -2.1 \times 10 = -21 \) m/s.

For part (c), you need to plot a velocity vs. time graph. The x-axis represents time in seconds, and the y-axis shows velocity in m/s. You should include:

- From 0 to 15 seconds, velocity increases from 0 to 27 m/s.
- From 15 to 65 seconds, velocity remains constant at 27 m/s.
- From 65

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Step 1: Determine the given data:

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Step 2: a) Draw acceleration time graph:

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Step 3: b) Find the change in velocity:

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Step 4: c) Draw Velocity time grah:

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Step 5: d) Find the total displacement:

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