1. A block of mass m, and a block of mass m₂ are connected by a light string as shown; the inclination of the ramp is 8. Friction is negligible. Assume that m₂> m₁. Ꮎ 8 1 Subpart 1: Draw FBDS In your notebook, draw a free body diagrams of m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m,g, and m₂g, the tension in the string 7 and the normal reaction N₁ of the table on m₁. Note: The choice of the coordinate axes for the two blocks can be different as shown below: m, 2 m, L Subpart 2: Set-Up Newton's Second Law Equations (i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and moq, or their components
1. A block of mass m, and a block of mass m₂ are connected by a light string as shown; the inclination of the ramp is 8. Friction is negligible. Assume that m₂> m₁. Ꮎ 8 1 Subpart 1: Draw FBDS In your notebook, draw a free body diagrams of m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m,g, and m₂g, the tension in the string 7 and the normal reaction N₁ of the table on m₁. Note: The choice of the coordinate axes for the two blocks can be different as shown below: m, 2 m, L Subpart 2: Set-Up Newton's Second Law Equations (i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and moq, or their components
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Need help on section (ii) equation for Fy=m2a2,y
Fy=m2g-T is incorrect.
Transcribed Image Text:1. A block of mass m, and a block of mass m₂ are connected by a light string as shown; the inclination of
the ramp is 8. Friction is negligible.
Assume that m₂> m₁.
Ꮎ
Subpart 1: Draw FBDs
In your notebook, draw a free body diagrams of m, and m₂ using the template as shown below. The
forces acting on the system are weights of the blocks, m,g, and meg, the tension in the string T and
the normal reaction N₁ of the table on m₁.
Note: The choice of the coordinate axes for the two blocks can be different as shown below:
8
1
m₁
a = 4.08
✓
m₂
Subpart 2: Set-Up Newton's Second Law Equations
(i) Newton's Second Law for m, in terms of weights of the blocks, m,g, and meg, or their components
in terms of the ramp angle 8, the tension in the string 7 and the normal reaction N₁ of the table on
m, can be written as (use the coordinate axes for signs of different forces):
ZF, T-m₁gsine✔✔=m₁a₁,x
2
ZFN₁-m₁gcosm₁a₁0
(ii) Newton's Second Law for m₂ in terms of weights of the blocks, m,g, and m₂g, or their
components in terms of the ramp angle the tension in the string 7 and the normal reaction N, of
the table on m, can be written as:
Note: The motion of m₂ is along the y-direction only.
ΣFy mag-TX✔=m₂a₂y
(iii) How are the magnitudes of a, and a₂ related? What are the directions of a, and a₂?
Magnitude:
A. la,l is greater than la₂l
B. la, is less than lagl
C. lal is equal to lagl
C.
Direction:
A. a, is in the positive x direction, and a₂ is in the positive y-direction.
*2
B. a, is in the positive x direction, and a2 is in the negative y-direction.
C. a, is in the negative x direction, and a₂ is in the positive y-direction.
D. a, is in the negative x direction, and an is in the negative y-direction.
B.
✓
Subpart 3: CALCULATE NUMERICAL VALUES
Let m₁ = 1.9 kg block and m₂ = 3.4 kg block. The ramp angle 9 = 39⁰.
(i) Find the acceleration for the two blocks.
or
(ii) Find the tension in the string.
T= 19.46
√ N
L
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