1. A banana company claims that the mean weight of their banana is 150 grams with a standarddeviation of 18 grams. Data generated from a sample of 49 bananas randomly selected indicated amean weight of 153.5grams per banana. Is there sufficient evidence to reject the company's claim? Usea = 0.05.From the given problem #1 discuss the following:1. define and illustrate the null hypothesis, alternative hypothesis, level of significance. (Provideexplanation)2. identify the parameter to be tested. (Provide Explanation)3. identify the appropriate form of test statistics. (Provide Explanation)4. identify the rejection and non-rejection regions and the critical values. (Provide Explanation)5. Make a conclusion base from the result you obtain. (Provide Explanation)6. identify if it is a Type I and Type IlI errors in claims and decisions (Provide Explanation)

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Answered: 1. A banana company cdlaims that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
11. Suppose we want to know whether or not the mean weight of a certain species of hamster is equal to 150 pounds. To test this, will perform a one-sample t-test at significance level a = 0.05 using the following steps: • Sample size n = 30 • Sample mean weight x = 130 • Sample standard deviations = 10.5 Step 1: State the hypotheses. Step 2: The level of significance, one/two-tailed test, degrees of freedom Step 3: Statistical Test Step 4: Computation Step 5: Decision Rule Step 6: Reject Ho or Failed to Reject Ho Step 7: Conclusion.
You may need to use the appropriate appendix table or technology to answer this questlon. Consider the following data for two independent random samples taken from two normal populations. Sample 1 11 8. 14 8. 10 6. Sample 2 7. 6. 7. 5. 8. (a) Compute the two sample means. (b) Compute the two sample standard deviations. (c) What is the point estimate of the difference between the two population means? (d) What is the 90% confidence interval estimate of the difference between the two population means? 3.
Aspirin is packed in 120 tab bottles with weight normally distributed with mean 600g and standard deviation 6g. Rejected bottles are those whose weight differs from the mean weight by 15g or more. That is, rejected bottles have weight either too small or too large. We want to find out how many bottles will be rejected from a daily production of 5000 bottles. 1,Do we have to calculate one z-score or two z-scores? 2. The negative z-score is 3. The positive z-score is 4.How many bottles, of the 5000, do we anticipate to have to reject?
0. A high school principal claims that the variance in the GPA of students in the graduating class is Tess than 0.39. You test this claim by sampling 31 seniors and find their GPA have a variance or 0.21. Ho:o? Ha:o2 < 0.39 (Claim) = 0.39 Is there enough evidence to reject Ho and support the principal's claim at a 0.10 level of significance? ohs A. No, the test statistic x? B. No, the test statistic x2 = 16.154 is not in the rejection region with critical value 40.256 C. Yes, the test statistic x? D. No, the test statistic x2 = 21.434 is not in the rejection region with critical value 20.599 E. Yes, the test statistic x? = 16.154 is in the rejection region with critical value 20.599 = 20.599 is not in the rejection region with critical value 21.434 %3D 20.599 is in the rejection region with critical value 16.154 %D
3. A researcher samples 5 colony of Species of K and 5 colonies of Species L, measures their sizes as: Species K Species L 4.7 5.3 5.2 4.6 6.1 4.1 5.8 4.8 5.2 4.2 а. Test if mean colony size of Species K and Species L are different from each other? Report a p-value. (You mav need to do an additional test to decide which test to apply for comparing the means) b. What is the power of the test in part a? С. The researcher would like to design a new experiment which will allow a two tailed hypothesis test with significance 0.05 and power 0.90. What should be the sample sizes nk and ni for Species K and Species L (use k = 1). %3D
10. The mean value of 130 observations is 17 and with variance equal to 0.98. Find 90% confidence interval of the population mean value.
Suppose the nutrition information on the package of Matilde's favorite brand of chips states that a serving size of 25 g equals about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample t-test with a significance level of a = 0.10 to test the null hypothesis, Ho: u = 2.08, against the alternative hypothesis, H1: µ # 2.08, where u is the average weight of a chip. Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for her test are shown in the following table. Sample size Sample mean Sample standard deviation Test statistic Probability value P-value 45 2.04 0.14 -2.076 0.044 Based on these results, complete the following sentences to state the decision and conclusion of the test.…
Identify the IV and the scale of measurement; Identify the DV and the scale of measurement and for the IV – identify the number of levels; Identify null and alternative hypotheses, are they directional or non-directional? Assume that the distributions of the populations are approximately normal.
2. A travel agent claims that the mean price of a round trip flight from San Francisco to Hawaii is less than $510. A simple random sample of 60 round trip flights from San Francisco to Hawaii has a mean price of $502. Assume the population standard deviation is $110. At a significance level of 5%, is there enough statistical evidence to support the travel agent's claim? Requirements: 1. 2. 3. Step 1: State the hypothesis: Họ: Ha: Tail Step 2: Draw your distribution and find critical number(s) Step 3: Compute the test statistics Step 4: Make a Decision: Step 5: Summarize the result: (Restate the level of significance and discuss the claim)
Now say the company randomly selects 10 independent reviews. We are interested in the number of 5 star reviews out of the 10 independent reviews. What is the probability that none of the 10 reviews are 5 stars (all 10 reviews are not 5 stars)?

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