1. a) A gas evolved during the fermentation of glucose (wine making) has a volume of 0.780 L at 20.1°C and 1.00 atm. What was the volume fermentation temperature of 36.5°C and 1.00 atm pressure? V= 0.78OL TI=20-1°c+ 273.15-293.2S T2=36.518 . P= 1.00 atm b) An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL, 0.60atm, and 45°C respectively. What was the initial volume?
1. a) A gas evolved during the fermentation of glucose (wine making) has a volume of 0.780 L at 20.1°C and 1.00 atm. What was the volume fermentation temperature of 36.5°C and 1.00 atm pressure? V= 0.78OL TI=20-1°c+ 273.15-293.2S T2=36.518 . P= 1.00 atm b) An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL, 0.60atm, and 45°C respectively. What was the initial volume?
Chemistry
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Chapter1: Chemical Foundations
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
Transcribed Image Text:. a) A gas evolved during the fermentation of glucose (wine making) has a volume of 0.780 L
at 20.1°C and 1.00 atm. What was the volume fermentation temperature of 36.5°C and 1.00
atm pressure? V=0.78OL
TI =20-1°c+ 273.15°7-293-2S
%3D
P= 1.00 atm
%3D
b) An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume,
pressure, and temperature were 94 mL, 0.60atm, and 45°C respectively. What was the
initial volume?
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