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1. 2. 3. OEt O 1.) NaOEt 2.) H30* OEt 1.) NaOEt 2.) H30* 1.) NaOEt 2.) 3.) H₂O*

1. 2. 3. OEt O 1.) NaOEt 2.) H30* OEt 1.) NaOEt 2.) H30* 1.) NaOEt 2.) 3.) H₂O*

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw the products of the following reactions. The mechanism is also provided. 

The image presents three chemical reaction schemes, each involving the reagent NaOEt (sodium ethoxide) followed by acidic workup with H₃O⁺ (hydronium ion). 1. **Reaction 1:** - **Starting Compound:** A β-keto ester, with a structure of a ketone on the β position relative to the ester. - **Reagents:** - 1.) NaOEt: A base used to deprotonate and form an enolate ion. - 2.) H₃O⁺: An acidic workup used to neutralize the reaction mixture. - **General Reaction Type:** Claisen Condensation. 2. **Reaction 2:** - **Starting Compound:** A β-diketone with an ester group, incorporating a phenyl ring. - **Reagents:** - 1.) NaOEt: Promotes formation of the enolate ion for a nucleophilic attack. - 2.) H₃O⁺: Used for acidic workup. - **General Reaction Type:** Claisen Condensation with an aromatic component. 3. **Reaction 3:** - **Starting Compound:** A ketone and an ester combination. - **Reagents:** - 1.) NaOEt: Forms the enolate anion. - 2.) An unspecified step indicated by a blank line, suggesting further reaction conditions or a secondary reactant might be involved. - 3.) H₃O⁺: Final acidic workup for the reaction. - **Product:** An α,β-unsaturated carbonyl compound as indicated by the structure of a double bond next to a carbonyl. Each reaction scheme involves typical reaction conditions for enolate chemistry under basic and subsequent acidic conditions. These reactions illustrate fundamental concepts in organic synthesis, specifically the formation of carbon-carbon bonds in carbonyl chemistry.
Transcribed Image Text:The image presents three chemical reaction schemes, each involving the reagent NaOEt (sodium ethoxide) followed by acidic workup with H₃O⁺ (hydronium ion). 1. **Reaction 1:** - **Starting Compound:** A β-keto ester, with a structure of a ketone on the β position relative to the ester. - **Reagents:** - 1.) NaOEt: A base used to deprotonate and form an enolate ion. - 2.) H₃O⁺: An acidic workup used to neutralize the reaction mixture. - **General Reaction Type:** Claisen Condensation. 2. **Reaction 2:** - **Starting Compound:** A β-diketone with an ester group, incorporating a phenyl ring. - **Reagents:** - 1.) NaOEt: Promotes formation of the enolate ion for a nucleophilic attack. - 2.) H₃O⁺: Used for acidic workup. - **General Reaction Type:** Claisen Condensation with an aromatic component. 3. **Reaction 3:** - **Starting Compound:** A ketone and an ester combination. - **Reagents:** - 1.) NaOEt: Forms the enolate anion. - 2.) An unspecified step indicated by a blank line, suggesting further reaction conditions or a secondary reactant might be involved. - 3.) H₃O⁺: Final acidic workup for the reaction. - **Product:** An α,β-unsaturated carbonyl compound as indicated by the structure of a double bond next to a carbonyl. Each reaction scheme involves typical reaction conditions for enolate chemistry under basic and subsequent acidic conditions. These reactions illustrate fundamental concepts in organic synthesis, specifically the formation of carbon-carbon bonds in carbonyl chemistry.
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