Draw the complete, detailed E1 mechanism for each of the following reactions, and show all resonance structures, where applicable.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Draw the complete, detailed E1 mechanism for each of the following reactions, and show all resonance structures, where applicable. 

**Title:** E1 Reaction Mechanisms

**Instruction:** Draw the complete, detailed E₁ mechanism for each of the following reactions.

**Reaction (a):**

- **Reactants**: Cyclohexyl bromide (a cyclohexane ring with a bromine substituent) reacts with methanol (CH₃OH).
- **Product**: Cyclohexene (a cyclohexane ring with a double bond).

**Explanation:** In this reaction, the E₁ mechanism involves the loss of the bromide ion from the cyclohexyl bromide to form a carbocation intermediate. Methanol acts as a nucleophile and solvent, facilitating the deprotonation to form the double bond and yield cyclohexene.

**Reaction (b):**

- **Reactants**: 2-Iodopentane (a pentane chain with an iodine substituent on the second carbon) reacts with water (H₂O).
- **Product**: 1-Pentene (a pentane chain with a double bond between the first and second carbon).

**Explanation:** In this E₁ reaction, the iodide ion leaves, forming a carbocation at the secondary carbon. Water acts as a base, abstracting a proton and forming a double bond at the end of the chain to create 1-pentene.
Transcribed Image Text:**Title:** E1 Reaction Mechanisms **Instruction:** Draw the complete, detailed E₁ mechanism for each of the following reactions. **Reaction (a):** - **Reactants**: Cyclohexyl bromide (a cyclohexane ring with a bromine substituent) reacts with methanol (CH₃OH). - **Product**: Cyclohexene (a cyclohexane ring with a double bond). **Explanation:** In this reaction, the E₁ mechanism involves the loss of the bromide ion from the cyclohexyl bromide to form a carbocation intermediate. Methanol acts as a nucleophile and solvent, facilitating the deprotonation to form the double bond and yield cyclohexene. **Reaction (b):** - **Reactants**: 2-Iodopentane (a pentane chain with an iodine substituent on the second carbon) reacts with water (H₂O). - **Product**: 1-Pentene (a pentane chain with a double bond between the first and second carbon). **Explanation:** In this E₁ reaction, the iodide ion leaves, forming a carbocation at the secondary carbon. Water acts as a base, abstracting a proton and forming a double bond at the end of the chain to create 1-pentene.
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