1) Draw the mechanism for the following reaction. Но H2SO4

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### Transcription:

**Question:**
1) Draw the mechanism for the following reaction.

**Chemical Reaction:**
- Starting Material: A secondary alcohol (skeletal structure shown as a straight chain with one carbon attached to an OH group).
- Reagents: 
  - Water (H₂O)
  - Sulfuric acid (H₂SO₄)
- Product: An alkene (skeletal structure shown as a straight chain with a double bond between two of the carbon atoms).

### Explanation:

This image illustrates an acid-catalyzed dehydration reaction. The secondary alcohol undergoes elimination in the presence of sulfuric acid (H₂SO₄) and water (H₂O) to form an alkene. 

**Mechanism Overview:**
1. **Protonation of the Alcohol Group:** The hydroxyl group of the alcohol is protonated by the acid, increasing its leaving group ability.
2. **Formation of Carbocation Intermediate:** Water is lost, leading to the formation of a carbocation intermediate.
3. **Carbocation Rearrangement (if applicable):** Depending on stability, the carbocation may rearrange.
4. **Elimination:** A beta-hydrogen is removed, forming a double bond and resulting in the alkene product.

This reaction is a key example of an E1 (unimolecular elimination) mechanism often studied in Organic Chemistry.

### Diagram Details:

- **Reactant**: The secondary alcohol is depicted with a carbon chain having an OH group.
- **Arrow indicating reaction progress**: Points from the alcohol to the alkene.
- **Conditions shown above arrow**: H₂O and H₂SO₄.

This educational diagram helps visualize the concepts of alcohol dehydration and alkene formation, critical in understanding organic synthesis pathways.

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Transcribed Image Text:Certainly! Below is a transcription and explanation suited for an educational website: --- ### Transcription: **Question:** 1) Draw the mechanism for the following reaction. **Chemical Reaction:** - Starting Material: A secondary alcohol (skeletal structure shown as a straight chain with one carbon attached to an OH group). - Reagents: - Water (H₂O) - Sulfuric acid (H₂SO₄) - Product: An alkene (skeletal structure shown as a straight chain with a double bond between two of the carbon atoms). ### Explanation: This image illustrates an acid-catalyzed dehydration reaction. The secondary alcohol undergoes elimination in the presence of sulfuric acid (H₂SO₄) and water (H₂O) to form an alkene. **Mechanism Overview:** 1. **Protonation of the Alcohol Group:** The hydroxyl group of the alcohol is protonated by the acid, increasing its leaving group ability. 2. **Formation of Carbocation Intermediate:** Water is lost, leading to the formation of a carbocation intermediate. 3. **Carbocation Rearrangement (if applicable):** Depending on stability, the carbocation may rearrange. 4. **Elimination:** A beta-hydrogen is removed, forming a double bond and resulting in the alkene product. This reaction is a key example of an E1 (unimolecular elimination) mechanism often studied in Organic Chemistry. ### Diagram Details: - **Reactant**: The secondary alcohol is depicted with a carbon chain having an OH group. - **Arrow indicating reaction progress**: Points from the alcohol to the alkene. - **Conditions shown above arrow**: H₂O and H₂SO₄. This educational diagram helps visualize the concepts of alcohol dehydration and alkene formation, critical in understanding organic synthesis pathways. ---
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