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1. 0.001n³ – 1000n² log n – 100n + 5 O (n³).

1. 0.001n³ – 1000n² log n – 100n + 5 O (n³).

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question 02: Use the definition of Big-Oh to prove that 1. 0.001n³ – 1000n² log n – 100n + 5 O (n³). %3D 2. n/100 = O(n) 3. n2 +100nlogn + 10n + 1000 = 0(n²)
Transcribed Image Text:Question 02: Use the definition of Big-Oh to prove that 1. 0.001n³ – 1000n² log n – 100n + 5 O (n³). %3D 2. n/100 = O(n) 3. n2 +100nlogn + 10n + 1000 = 0(n²)
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