Differentiate y = (9x- 11) log3 (1læ – 9). %3D A. y' = 9(11x-9)+11(9z-11) In(9r-11) (9x-11) In(3) %3D B. y' = 9(11-9) In(3)+11(92-11) In(9x–11) In(3) %3D (9ӕ-11) C. y' 11(9x-11)+9(11r-9) In(11a-9) (11a-9) In(3) %3D 11(9r-11) In(3)+9(11x-9) ln(11æ-9) In(3) D. y' (11g
Differentiate y = (9x- 11) log3 (1læ – 9). %3D A. y' = 9(11x-9)+11(9z-11) In(9r-11) (9x-11) In(3) %3D B. y' = 9(11-9) In(3)+11(92-11) In(9x–11) In(3) %3D (9ӕ-11) C. y' 11(9x-11)+9(11r-9) In(11a-9) (11a-9) In(3) %3D 11(9r-11) In(3)+9(11x-9) ln(11æ-9) In(3) D. y' (11g
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter1: Systems Of Linear Equations
Section1.3: Applications Of Systems Of Linear Equations
Problem 14E: Use log21=0,log22=1, and log24=2 to estimate log23.
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![Differentiate y = (9x- 11) log3 (1læ – 9).
A. y'
9(11x-9)+11(9x–11) In(9x-11)
%3D
(9x-11) In(3)
B. y'
9(11-9) In(3)+11(9x-11) In(92-11) In(3)
(9x-11)
C. y'
11(9x–11)+9(11a-9) In(11x-9)
(11x-9) In(3)
D. y'
11(9x–11) In(3)+9(11x-9) In(11x-9) In(3)
(11x -9)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb7a38356-9ffa-42a9-a903-f81e2cad11ff%2Fcd40041a-5fec-45a4-ac11-592634c74ff6%2Fyxghdeb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Differentiate y = (9x- 11) log3 (1læ – 9).
A. y'
9(11x-9)+11(9x–11) In(9x-11)
%3D
(9x-11) In(3)
B. y'
9(11-9) In(3)+11(9x-11) In(92-11) In(3)
(9x-11)
C. y'
11(9x–11)+9(11a-9) In(11x-9)
(11x-9) In(3)
D. y'
11(9x–11) In(3)+9(11x-9) In(11x-9) In(3)
(11x -9)
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