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(1) Solve the following: (a) 42x-1 = 64 (d) In 3- Inx- In(x+ 5) = 0 (b) 81-x = 4x+2 (c) 22x + 2%– 12 = 0 (e) log4(x+ 2) – log4 (x- 1) = 1 %3D () log2 (x- 1) – log2(x+ 3) = log2 %3D

(1) Solve the following: (a) 42x-1 = 64 (d) In 3- Inx- In(x+ 5) = 0 (b) 81-x = 4x+2 (c) 22x + 2%– 12 = 0 (e) log4(x+ 2) – log4 (x- 1) = 1 %3D () log2 (x- 1) – log2(x+ 3) = log2 %3D

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Need answer for Question 1.( E)and 1.(f)

and Question 3.

(1) Solve the following: (a) 42x-1 = 64 3D64 (b) 81-x = 4x+2 (c) 22x + 2x- 12 0 (e) log,(x+ 2) – log4(x- 1) = 1 (d) In 3- Inx – In(x+ 5) = 0 (f) log2 (x- 1) – log2(x+ 3) = log2 (2) The price of a dress is reduced by 20%. When the dress still does not sell, price was then reduced by 10% of the reduced price. If the price of the dress after both reductions is $264, what was the original price? (3) If a projectile is launched into the air at 29.4 feet per second from a height of 60 feet, its height (in feet) is given by S(x) = 60 + 29.4x – Showing all working, determine: 9.8x², where x is in seconds:
Transcribed Image Text:(1) Solve the following: (a) 42x-1 = 64 3D64 (b) 81-x = 4x+2 (c) 22x + 2x- 12 0 (e) log,(x+ 2) – log4(x- 1) = 1 (d) In 3- Inx – In(x+ 5) = 0 (f) log2 (x- 1) – log2(x+ 3) = log2 (2) The price of a dress is reduced by 20%. When the dress still does not sell, price was then reduced by 10% of the reduced price. If the price of the dress after both reductions is $264, what was the original price? (3) If a projectile is launched into the air at 29.4 feet per second from a height of 60 feet, its height (in feet) is given by S(x) = 60 + 29.4x – Showing all working, determine: 9.8x², where x is in seconds:
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