Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![1
¹5 (5² + 4) = = = √ ² ²
S
+4
x-1(e-s (5 + 3) - 16)
s+ 3
S
(5(t-)cos3t) = 25² + 18
e-255
(5+2)² 16.
= 4₂(t)e-2 (1-2
e
=
(S-1)² +9 - 4(1)(-5)
L(tsint)=
25
s² + 1
If f(t) = = { '3+ (1-6)²
{t
t<6
t ≥6
7.
1
then Lif(t)) ==+(2+)-6:
5²
2
45'e
82(t-1)dr) = ((s + 1)² + 4)(5 + 1)²
е - 1)
0
21
=t6e²1
-- ² (6 - 1²) =
9.
10.-(5(t-)sint) = e
1.
2.
3.
4.
5.
6.
8.
sin2t.dt
=u₁(t)e-3(1-¹) cosh4t
S
-2)[cosh(4(t-2)) -0.5sinh4(t-2)]
cos3t](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10701e48-c966-4bf0-a75a-6068bccd8e90%2F8cc40935-d7ac-4faa-ab61-041490df6234%2Fejkrtao_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1
¹5 (5² + 4) = = = √ ² ²
S
+4
x-1(e-s (5 + 3) - 16)
s+ 3
S
(5(t-)cos3t) = 25² + 18
e-255
(5+2)² 16.
= 4₂(t)e-2 (1-2
e
=
(S-1)² +9 - 4(1)(-5)
L(tsint)=
25
s² + 1
If f(t) = = { '3+ (1-6)²
{t
t<6
t ≥6
7.
1
then Lif(t)) ==+(2+)-6:
5²
2
45'e
82(t-1)dr) = ((s + 1)² + 4)(5 + 1)²
е - 1)
0
21
=t6e²1
-- ² (6 - 1²) =
9.
10.-(5(t-)sint) = e
1.
2.
3.
4.
5.
6.
8.
sin2t.dt
=u₁(t)e-3(1-¹) cosh4t
S
-2)[cosh(4(t-2)) -0.5sinh4(t-2)]
cos3t
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