(Sin X-cos X)^2=1-sin 2x

Q: Sinx=1/2 Cos2x=

A:

Q: 2 cos^2 x-sin x -1=0

A: 2cos2x-sinx-1=0⇒1-sinx-2sin2x=0⇒sinx=-1, sinx=12⇒x=3π2+2πn, x=π6+2πn, x=5π6+2πn

Q: Differentiate y = (-6+sinx)/(x+cosx)

A:

Q: 2. ( sin32x dx cos 2x

A: We have to integrate.

Q: (1+cos3x)² -dx sin23x

A:

Q: -1 L tsin(2t) 4

A: Given function is  Let f(t)= 1/4 tsin(2t)

Q: sin 2x (1 - 2 cos 2x)? dx 6.

A:

Q: Solve for x: sin^2 x -cos^2 x+1=0

A: Solve the equation

Q: (sin A)^4-(cos A)^4

A:

Q: (1-sin9x)²dx

A: To evaluate the given integral

Q: 3 cos xdx 1-sinx

A:

Q: Ja (1 – sinx)3/2 (1+ sinx)²dx"

A: If , then the independent variable x is called the input of the function and the dependent variable…

Q: cos x-sinxtanx=

A:

Q: Evaluate sin2xlogtanx dx

A: Given:  Let I=∫0π2 sin2xlogtan x dx To Find: To evaluate the given integral.

Q: cosx+1=sinx

A: