θ = cos^-1[sin(LT1) sin(LT2) + cos(LT1) cos(LT2) cos(LN1 − LN2)] How does this formula go with latitude and longitude corrdinates?

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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θ = cos^-1[sin(LT1) sin(LT2) + cos(LT1) cos(LT2) cos(LN1 − LN2)]

How does this formula go with latitude and longitude corrdinates?

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Step 1: Solution

Advanced Math homework question answer, step 1, image 1

Consider the figure as our Earth.

O is the center of the earth

Point P on the earth surface has Latitude =φ and Longitude λ

In general we take :

-180°<λ180°  -90°φ90°ρ=OP=3960 miles

where ρ is the radius of the Earth

With respect to the Cartesian co-ordinates axes: x, y  and z we have

ρ=xp,yp,zp=ρcosλcosφ, ρsinλcosφ, ρsinφ       .......(1)

If ρOQ=OQ=Distance from Q to the center of the earth in the figure above, then

Q=xQ,yQ,zQ=ρOQcosλcosφ,ρOQsinλcosφ, ρOQsinφ           .....2

the straight line , linear distance P1P2 between any two point P1 and P2 in 3-space may be computed from their Cartesian Coordinates.

If P1=x1,y1,z1 and P2=x2,y2,z2 then P1P2=x2-x12+y2-y12+z2-z12        ...3

If θ=POR is the angle formed between any two points P and R on the surface of the Earth with O, the center of the Earth, then

θ=cos-1sinφPsinφR+cosφPcosφRcosλP-λR        ...(4)

In the above formula , assume P has (Longitude=λP=LN1; Longitude=φP=LT1)

and R has (Longitude=λR=LN2; Longitude=φR=LT2)

The geodesic or surface distance, SDPR,, between the points P and R measured along a great circle of the Earth is

SDPR=θ°180°·3960π miles   (5) where θ°=POR

 

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