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1) When 1-pentanol is heated with HCI/ZnCl2, 1-chloropentane is the major product. This is an reaction, and, is also produced as product. A) SN1, H₂O B) SN2, H₂O C) SN1, H2 D) SN2, H2 E) E2, H2 2) Draw the product of the following reaction: 1. BH, THE 2. HƠ, H,9, 3. PCC 3) Which of the following statements is not true? A. Primary, secondary, and tertiary alcohols all undergo nucleophilic substitution with HI, HBr, and HCl. B. Carbocation stability: 1°> 2*> 3* C. Tertiary alcohols undergo SN1 reactions with hydrogen halides. D. Primary alcohols undergo SN2 reactions with hydrogen halides. E. An alcohol has a strongly basic leaving group that cannot be displaced by a nucleophile. 4) Using reagents such as SOCI₂ or PBrs, alcohols are converted into alkyl halides. This approach A. inverts the configuration if the OH group is bonded to an asymmetric center

1) When 1-pentanol is heated with HCI/ZnCl2, 1-chloropentane is the major product. This is an reaction, and, is also produced as product. A) SN1, H₂O B) SN2, H₂O C) SN1, H2 D) SN2, H2 E) E2, H2 2) Draw the product of the following reaction: 1. BH, THE 2. HƠ, H,9, 3. PCC 3) Which of the following statements is not true? A. Primary, secondary, and tertiary alcohols all undergo nucleophilic substitution with HI, HBr, and HCl. B. Carbocation stability: 1°> 2*> 3* C. Tertiary alcohols undergo SN1 reactions with hydrogen halides. D. Primary alcohols undergo SN2 reactions with hydrogen halides. E. An alcohol has a strongly basic leaving group that cannot be displaced by a nucleophile. 4) Using reagents such as SOCI₂ or PBrs, alcohols are converted into alkyl halides. This approach A. inverts the configuration if the OH group is bonded to an asymmetric center

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1) When 1-pentanol is heated with HCI/ZnCl2, 1-chloropentane is the major product. This is an is also produced as product. reaction, and A) SN1, H₂O B) SN2, H₂O C) SN1, H₂ D) SN2, H2 E) E2, H2 Chapter 10 2) Draw the product of the following reaction: 1. BH, THE 2 HỒ, HyOy 3. PCC 3) Which of the following statements is not true? A. Primary, secondary, and tertiary alcohols all undergo nucleophilic substitution with HI, HBr, and HCI. B. Carbocation stability: 1*> 2* > 3* C. Tertiary alcohols undergo SN1 reactions with hydrogen halides. D. Primary alcohols undergo SN2 reactions with hydrogen halides. E. An alcohol has a strongly basic leaving group that cannot be displaced by a nucleophile. 4) Using reagents such as SOCI₂ or PBrą, alcohols are converted into alkyl halides. This approach A. B. C. D. E. inverts the configuration if the OH group is bonded to an asymmetric center converts the OH group into a better leaving group works well for 1" and 2* alcohols creates a leaving group that is a weaker base than the halide ion does all of the above
Transcribed Image Text:1) When 1-pentanol is heated with HCI/ZnCl2, 1-chloropentane is the major product. This is an is also produced as product. reaction, and A) SN1, H₂O B) SN2, H₂O C) SN1, H₂ D) SN2, H2 E) E2, H2 Chapter 10 2) Draw the product of the following reaction: 1. BH, THE 2 HỒ, HyOy 3. PCC 3) Which of the following statements is not true? A. Primary, secondary, and tertiary alcohols all undergo nucleophilic substitution with HI, HBr, and HCI. B. Carbocation stability: 1*> 2* > 3* C. Tertiary alcohols undergo SN1 reactions with hydrogen halides. D. Primary alcohols undergo SN2 reactions with hydrogen halides. E. An alcohol has a strongly basic leaving group that cannot be displaced by a nucleophile. 4) Using reagents such as SOCI₂ or PBrą, alcohols are converted into alkyl halides. This approach A. B. C. D. E. inverts the configuration if the OH group is bonded to an asymmetric center converts the OH group into a better leaving group works well for 1" and 2* alcohols creates a leaving group that is a weaker base than the halide ion does all of the above
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