1) We left off with the car example in lecture when our car (m=2000kg) had a speed of v=.24m/s and the engine force%3D70N and wind resistance= -70N. Now lets see what happens if we decrease the engine force to. 50N, as seen below. V;=. 24 Vp=0% %3D te=50N
1) We left off with the car example in lecture when our car (m=2000kg) had a speed of v=.24m/s and the engine force%3D70N and wind resistance= -70N. Now lets see what happens if we decrease the engine force to. 50N, as seen below. V;=. 24 Vp=0% %3D te=50N
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The image attached, please answer question 1 parts a and b.

Transcribed Image Text:**Work and Simple Machines**
1) We left off with the car example in lecture when our car (m=2000 kg) had a speed of \( v_i = 0.24 \, \text{m/s} \) and the engine force \( F_e = 70 \, \text{N} \) and wind resistance \( = -70 \, \text{N} \). Now let's see what happens if we decrease the engine force to 50N, as shown below.
*Diagram Explanation:*
- The diagram shows a car at two different points:
- **Initial Position:** A car with forces indicated. The engine force \( F_e = 50 \, \text{N} \) is shown with an arrow in the direction of motion. The wind resistance \( = -70 \, \text{N} \) acts opposite to the direction of motion.
- **Final Position:** The car comes to rest with a final velocity \( v_f = 0 \, \text{m/s} \).
a) Is the car speeding up or slowing down?
b) Find the distance the car will move as it comes to rest.
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