(1) v2T V2ㅠ 21+ e-2 eTaz 0003 1 •.. v2ㅠ 32+을 e-3 eTds 0|00|1 (2) 32+ e-3 e 12-3 .. (3) V2T 43+3 e-4 e4 0002 6. ... (4) V2π eTs 54+을 e-5 е 12.5 %3D (5) V2T eTa6 65+을 e-6 е 12.6 ... (6) V2ㅠ 76+ e-7 etT 76+를 e-7 е 12.7 ... 2] ||

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Mathematical Expressions with Diagrams

Below are a series of mathematical expressions involving constants, exponents, and the natural exponential function, paired with box diagrams.

#### Expressions

1. \(\sqrt{2\pi} \cdot 11^{0 + \frac{1}{2}} \cdots e^{-11} \cdot e^{\frac{1}{{12 \cdot 11}}}\) \\
   = ![ ](insert_box_diagram_placeholder) ![ ](ellipsis_placeholder) ...

2. \(\sqrt{2\pi} \cdot 12^{1 + \frac{1}{2}} \cdots e^{-12} \cdot e^{\frac{1}{{12 \cdot 12}}}\) \\
   = ![ ](second_box_diagram_placeholder) ![ ](ellipsis_placeholder) ...

3. \(\sqrt{2\pi} \cdot 13^{2 + \frac{1}{2}} \cdots e^{-13} \cdot e^{\frac{1}{{12 \cdot 13}}}\) \\
   = ![ ](third_box_diagram_placeholder) ![ ](ellipsis_placeholder) ...

4. \(\sqrt{2\pi} \cdot 14^{3 + \frac{1}{2}} \cdots e^{-14} \cdot e^{\frac{1}{{12 \cdot 14}}}\) \\
   = ![ ](fourth_box_diagram_placeholder) ![ ](ellipsis_placeholder) ...

5. \(\sqrt{2\pi} \cdot 15^{4 + \frac{1}{2}} \cdots e^{-15} \cdot e^{\frac{1}{{12 \cdot 15}}}\) \\
   = ![ ](fifth_box_diagram_placeholder) ![ ](ellipsis_placeholder) ...

6. \(\sqrt{2\pi} \cdot 16^{5 + \frac{1}{2}} \cdots e^{-16} \cdot e^{\frac{1}{{12 \cdot 16}}}\) \\
   = ![ ](sixth_box_diagram_placeholder) ![ ](ellipsis_placeholder) ...

7. \(\sqrt{2\pi} \cdot 17^{6 + \
Transcribed Image Text:### Mathematical Expressions with Diagrams Below are a series of mathematical expressions involving constants, exponents, and the natural exponential function, paired with box diagrams. #### Expressions 1. \(\sqrt{2\pi} \cdot 11^{0 + \frac{1}{2}} \cdots e^{-11} \cdot e^{\frac{1}{{12 \cdot 11}}}\) \\ = ![ ](insert_box_diagram_placeholder) ![ ](ellipsis_placeholder) ... 2. \(\sqrt{2\pi} \cdot 12^{1 + \frac{1}{2}} \cdots e^{-12} \cdot e^{\frac{1}{{12 \cdot 12}}}\) \\ = ![ ](second_box_diagram_placeholder) ![ ](ellipsis_placeholder) ... 3. \(\sqrt{2\pi} \cdot 13^{2 + \frac{1}{2}} \cdots e^{-13} \cdot e^{\frac{1}{{12 \cdot 13}}}\) \\ = ![ ](third_box_diagram_placeholder) ![ ](ellipsis_placeholder) ... 4. \(\sqrt{2\pi} \cdot 14^{3 + \frac{1}{2}} \cdots e^{-14} \cdot e^{\frac{1}{{12 \cdot 14}}}\) \\ = ![ ](fourth_box_diagram_placeholder) ![ ](ellipsis_placeholder) ... 5. \(\sqrt{2\pi} \cdot 15^{4 + \frac{1}{2}} \cdots e^{-15} \cdot e^{\frac{1}{{12 \cdot 15}}}\) \\ = ![ ](fifth_box_diagram_placeholder) ![ ](ellipsis_placeholder) ... 6. \(\sqrt{2\pi} \cdot 16^{5 + \frac{1}{2}} \cdots e^{-16} \cdot e^{\frac{1}{{12 \cdot 16}}}\) \\ = ![ ](sixth_box_diagram_placeholder) ![ ](ellipsis_placeholder) ... 7. \(\sqrt{2\pi} \cdot 17^{6 + \
## Problem

In each line, give an approximate value in decimals using a calculator.

1. \(\sqrt{2\pi} \cdot 2^{1+\frac{1}{2}} \cdot e^{-2} \cdot e^{\frac{1}{12 \cdot 2}} =\) 1.0003...
   
2. \(\sqrt{2\pi} \cdot 3^{2+\frac{1}{2}} \cdot e^{-3} \cdot e^{\frac{1}{12 \cdot 3}} =\) 2.0001...
   
3. \(\sqrt{2\pi} \cdot 4^{3+\frac{1}{2}} \cdot e^{-4} \cdot e^{\frac{1}{12 \cdot 4}} =\) 6.0002...

4. \(\sqrt{2\pi} \cdot 5^{4+\frac{1}{2}} \cdot e^{-5} \cdot e^{\frac{1}{12 \cdot 5}} =\)
   
5. \(\sqrt{2\pi} \cdot 6^{5+\frac{1}{2}} \cdot e^{-6} \cdot e^{\frac{1}{12 \cdot 6}} =\)
   
6. \(\sqrt{2\pi} \cdot 7^{6+\frac{1}{2}} \cdot e^{-7} \cdot e^{\frac{1}{12 \cdot 7}} =\) 

7. \(\sqrt{2\pi} \cdot 8^{7+\frac{1}{2}} \cdot e^{-8} \cdot e^{\frac{1}{12 \cdot 8}} =\)
   
8. \(\sqrt{2\pi} \cdot 9^{8+\frac{1}{2}} \cdot e^{-9} \cdot e^{\frac{1}{12 \cdot 9}} =\) 

9. \(\sqrt{2\pi} \cdot 10^{9+\frac{1}{2}} \cdot e^{-10} \cdot e^{\frac{1}{12 \cdot 10}} =\
Transcribed Image Text:## Problem In each line, give an approximate value in decimals using a calculator. 1. \(\sqrt{2\pi} \cdot 2^{1+\frac{1}{2}} \cdot e^{-2} \cdot e^{\frac{1}{12 \cdot 2}} =\) 1.0003... 2. \(\sqrt{2\pi} \cdot 3^{2+\frac{1}{2}} \cdot e^{-3} \cdot e^{\frac{1}{12 \cdot 3}} =\) 2.0001... 3. \(\sqrt{2\pi} \cdot 4^{3+\frac{1}{2}} \cdot e^{-4} \cdot e^{\frac{1}{12 \cdot 4}} =\) 6.0002... 4. \(\sqrt{2\pi} \cdot 5^{4+\frac{1}{2}} \cdot e^{-5} \cdot e^{\frac{1}{12 \cdot 5}} =\) 5. \(\sqrt{2\pi} \cdot 6^{5+\frac{1}{2}} \cdot e^{-6} \cdot e^{\frac{1}{12 \cdot 6}} =\) 6. \(\sqrt{2\pi} \cdot 7^{6+\frac{1}{2}} \cdot e^{-7} \cdot e^{\frac{1}{12 \cdot 7}} =\) 7. \(\sqrt{2\pi} \cdot 8^{7+\frac{1}{2}} \cdot e^{-8} \cdot e^{\frac{1}{12 \cdot 8}} =\) 8. \(\sqrt{2\pi} \cdot 9^{8+\frac{1}{2}} \cdot e^{-9} \cdot e^{\frac{1}{12 \cdot 9}} =\) 9. \(\sqrt{2\pi} \cdot 10^{9+\frac{1}{2}} \cdot e^{-10} \cdot e^{\frac{1}{12 \cdot 10}} =\
Expert Solution
Step 1

Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and specify the other subparts (up to 3) you’d like answered.

Using calculator I have found the values. The first three values were not right. I have fixed them.

Calculus homework question answer, step 1, image 1

 

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