Differentiate. g(x) = (x-5 + 3) (x-3+5) - 4 - 25x - 4 - 9x - 9 O A. g'(x) = - 8x X6- 9- - 25x- 9x -7 - 25x 4 O B. g'(x) = -8x -9 OC. g'(x) = -8x O D. g'(x) = - 8x -9 25x -6-9x2
Differentiate. g(x) = (x-5 + 3) (x-3+5) - 4 - 25x - 4 - 9x - 9 O A. g'(x) = - 8x X6- 9- - 25x- 9x -7 - 25x 4 O B. g'(x) = -8x -9 OC. g'(x) = -8x O D. g'(x) = - 8x -9 25x -6-9x2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![Differentiate.
g(x) = (x-5 + 3) (x¯³ + 5)
%3D
O A. g'(x)= -8x-25x
- 4
9x
-4
O B. g'(x) = -8x-25x
-6-9x*
-4
OC. g'(x) = -8x
9-
-25x
-4
|
X6-
O D. g'(x) = -8x
-9
-25x
-6
- 9x-2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6f527874-788c-4348-a581-50237b5b9478%2Fe06c3351-7fe1-4675-ac08-85b2a6cfc7f2%2Fpt89xe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Differentiate.
g(x) = (x-5 + 3) (x¯³ + 5)
%3D
O A. g'(x)= -8x-25x
- 4
9x
-4
O B. g'(x) = -8x-25x
-6-9x*
-4
OC. g'(x) = -8x
9-
-25x
-4
|
X6-
O D. g'(x) = -8x
-9
-25x
-6
- 9x-2
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