1) The equation for finding the water head in an open channel flow is given below. is given. In this equation, the channel width (B=8 units) and the flow rate of the water in the channel (Q=5 units) Since the height of the water in the channel is estimated to be between x1=0 and x2=2 units, What is the actual height (H) of the water in the channel? (You can make your transactions less than 0.05% of the approximate error.) continue until it is lower than and take six digits after the comma) 0.471405 x ( BH)5/3 (в + 2хН)2/3 f(H) = %3D

1) The equation for finding the water head in an open channel flow is given below. is given. In this equation, the channel width (B=8 units) and the flow rate of the water in the channel (Q=5 units) Since the height of the water in the channel is estimated to be between x1=0 and x2=2 units, What is the actual height (H) of the water in the channel? (You can make your transactions less than 0.05% of the approximate error.) continue until it is lower than and take six digits after the comma) 0.471405 x ( BH)5/3 (в + 2хН)2/3 f(H) = %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Fluid Dynamics

The study of the flow of gases and liquids, usually in and around solid surfaces, is known as fluid dynamics in physics and engineering. Fluid dynamics, for example, can be used to evaluate the movement of air through an airplane wing or the surface of a vehicle. It can also be used in ship design to increase the speed at which ships pass through water.

Question

1) The equation for finding the water head in an open channel flow is given below. is given. In this
equation, the channel width (B=8 units) and the flow rate of the water in the channel (Q=5 units)
Since the height of the water in the channel is estimated to be between x1-0 and x2=2 units, What is
the actual height (H) of the water in the channel? (You can make your transactions less than 0.05% of
the approximate error.) continue until it is lower than and take six digits after the comma)
0.471405 x ( BH)5/%
f(H) =
%3D
(B + 2 x H)2/3

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