1) SOCрyridine 2) CH3O- d) 1) TsC/pyridine 2) CH30 e) "OH HBr f) "OH

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Draw the major product of the following reactions. Please answer D, E, and F only.  Thank you

This image depicts a series of organic chemistry reactions aimed at transforming a cyclohexanol derivative into different products using various reagents and conditions.

1. **Reaction b)**:
   - Starting material: An epoxide 
   - Reagent: Methoxide ion in methanol (MeO⁻/MeOH)
   - Description: The epoxide is opened, typically resulting in a methoxy alcohol.

2. **Reaction c)**:
   - Starting material: Cyclohexanol 
   - Reagents:
     1. PBr₃/pyridine
     2. Methoxide ion (CH₃O⁻)
   - Description: Initially, cyclohexanol reacts with phosphorus tribromide (PBr₃) to form an alkyl bromide intermediate, which further reacts with methoxide ion to produce a methoxy compound.

3. **Reaction d)**:
   - Starting material: Cyclohexanol
   - Reagents:
     1. SOCl₂/pyridine
     2. Methoxide ion (CH₃O⁻)
   - Description: The alcohol is first converted to an alkyl chloride using thionyl chloride (SOCl₂) and pyridine. This chloride then reacts with methoxide ion to yield a methoxy compound.

4. **Reaction e)**:
   - Starting material: Cyclohexanol
   - Reagents:
     1. TsCl/pyridine
     2. Methoxide ion (CH₃O⁻)
   - Description: Cyclohexanol is treated with tosyl chloride (TsCl) and pyridine to form the tosylate ester, which is subsequently displaced by methoxide ion to form a methoxy derivative.

5. **Reaction f)**:
   - Starting material: Cyclohexanol
   - Reagent: Hydrobromic acid (HBr) with heat (∆)
   - Description: The alcohol undergoes a reaction with HBr, typically resulting in the formation of an alkyl bromide through an elimination followed by a substitution reaction.

This sequence of reactions highlights the transformation of alcohol functional groups via different substitution and elimination mechanisms using different reagents.
Transcribed Image Text:This image depicts a series of organic chemistry reactions aimed at transforming a cyclohexanol derivative into different products using various reagents and conditions. 1. **Reaction b)**: - Starting material: An epoxide - Reagent: Methoxide ion in methanol (MeO⁻/MeOH) - Description: The epoxide is opened, typically resulting in a methoxy alcohol. 2. **Reaction c)**: - Starting material: Cyclohexanol - Reagents: 1. PBr₃/pyridine 2. Methoxide ion (CH₃O⁻) - Description: Initially, cyclohexanol reacts with phosphorus tribromide (PBr₃) to form an alkyl bromide intermediate, which further reacts with methoxide ion to produce a methoxy compound. 3. **Reaction d)**: - Starting material: Cyclohexanol - Reagents: 1. SOCl₂/pyridine 2. Methoxide ion (CH₃O⁻) - Description: The alcohol is first converted to an alkyl chloride using thionyl chloride (SOCl₂) and pyridine. This chloride then reacts with methoxide ion to yield a methoxy compound. 4. **Reaction e)**: - Starting material: Cyclohexanol - Reagents: 1. TsCl/pyridine 2. Methoxide ion (CH₃O⁻) - Description: Cyclohexanol is treated with tosyl chloride (TsCl) and pyridine to form the tosylate ester, which is subsequently displaced by methoxide ion to form a methoxy derivative. 5. **Reaction f)**: - Starting material: Cyclohexanol - Reagent: Hydrobromic acid (HBr) with heat (∆) - Description: The alcohol undergoes a reaction with HBr, typically resulting in the formation of an alkyl bromide through an elimination followed by a substitution reaction. This sequence of reactions highlights the transformation of alcohol functional groups via different substitution and elimination mechanisms using different reagents.
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