1) Show that 21 P(x) Pt-1(x) dx 412 - 1'
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- KE = mv², KE = 1w², Ug = mgh, U₁ = ¹kx², E = KE + Ug + Us, E₁ = Ef L = mrv, 1 =1wRadioactive Pm-147 decays by the release of a beta-particle with an averageenergy of 62.0 keV. A sample of Pm-147 serves as a radionuclide power source. It has anactivity of 4.64×105 Curies. How much thermal power in watts does the Pm-147 sampleproduce?S Scho X S Post- X d AI2 S x G The fx G rocke x S How bcps.schoology.com/common-assessment-delivery/start/6425623769?action=onresume&submissionid=969196920 NGLSync Portal Ho... S week of 12/20 Meet- nfw-jxsi-wtd Post-Assessment Unit 1 LC2 Potential Energy This Potential Energy Diagram represents an exothermic reaction; excess energy is released when the products are formed. A B C Reaction Coordinate 71 D The potential energy of the reactants is represented by the letter # The potential energy of the products is represented by the letter с E Highlight $ Quizizz CP CPM eBooks Index... % A O Mycoplasma pneu.... & a Qui 1 2 0
- Vapor pressure of a pure component (Psat) can be computed from the correlation equations. Beattie et al.(1951) gives the following equation between 50.00 to 160.60 °C for neopentane: 1136.462 log10 pat = 3.901633 + 4.99118 10-4 T T (temperature in K and vapor pressure is in atmospheres). The critical temperature (Te) and critical pressure (Pc) of neopentane are 160.60°C and 31.57 atmospheres respectively. Using the information given above and the class notes, answer the questions #1. 1. The acentric factor w is used a characterization parameter in phase behavior calculations. Acentric factor is a measure of sphericity of a molecule. The definition of w is given below. psat @ =- log10 --1.0 prat is calculated at T/Tc= 0.7 Pc Here Pal is the vapor pressure of the component and, P. and T are critical properties of the component. Psat/P¢and T/Tc must be unitless (T and Tc must be in R or K). Calculate the acentric factor of neopentane (CSH12) using Antoine vapor pressure equation. (In data…Please include FBD. Thank you!In a controlled fusion reactor Deuterium-Tritium The temperature of the plasma is T = 10 keV, where k is the k Boltzmann constant. The ions' number density is 2.6×10¹8 m-3. -22 3 Moreover (ov) = 10-²²m³s-¹, where o is the reaction cross-section, v is the relative speed of the reacting particles, and represents averaging according to the Maxwell- Boltzmann distribution. fusion is occurring. For what value of the confinement time does the reactor achieve the break even point? Enter your answer in seconds to 1 decimal point.
- (b) Consider a 100 cm² photovoltaic cell with reverse saturation current density of Jo = 10-¹² A/cm². In full sun, it produces a short-circuit current of 40 mA at 20 °C. Calculate the open-circuit voltage at full sun. Consider Boltzmann's constant as kB = 1.381 x 10-23 J.K-1 1.6 x 10-1⁹ C and T(K) = 273.15+T(°C) The open-circuit voltage, Voc, for a PV is: KBT, Voc = -In(+1) q lo Isc I q=3. A GM counter has dead time of 250 s. It records 20,000 counts per minute. What is the actual count rate? [Ans. 21,820]Question A7 Consider the fusion reaction Calculate the kinetic energy of 4He. 15NH 12C + 4 He.
- P FEUILLE DE COMPOSITION / Writing Paper Ex02 FMS EMPS AA+ The beam below is articulated at B and Sumply Supported at A. It us loaded as shown in the diagram Guven data: 0 = 45° F= 750N F2 = 1500N, F3 = 600 N Fx = 600N F5 = 1000N. ally the reactions RA and Determine graphically P P RB.The electric potential difference AV, also called voltage, is expressed in terms of the electric field as follows AV = | Edr a where, a is the initial position and b is the final position. If an electric field in a region in space is defined as E= Br where B is just a constant without an arbitrary value. What is the electric potential difference from position 0 to R? 1 AV = BR3 3 1 AV = BR3 AV = 1 (1– B)aR³ 2 AV = Br3 O AV = -(1-B)aR³ 1 AV = Br3 1 AV = BR2How many Rh R h atoms would have to be placed side by side to span a distance of 9.5 μm μ m ?