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Vapor pressure of a pure component (Psat) can be computed from the correlation equations. Beattie et al.(1951) gives the following equation between 50.00 to 160.60 °C for neopentane: 1136.462 log1o psat = 3.901633 - :+ 4.99118 10-4 T T (temperature in K and vapor pressure is in atmospheres). The critical temperature (Tc) and

Vapor pressure of a pure component (Psat) can be computed from the correlation equations. Beattie et al.(1951) gives the following equation between 50.00 to 160.60 °C for neopentane: 1136.462 log1o psat = 3.901633 - :+ 4.99118 10-4 T T (temperature in K and vapor pressure is in atmospheres). The critical temperature (Tc) and

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Vapor pressure of a pure component (Psat) can be computed from the correlation equations. Beattie et al.(1951) gives the following equation between 50.00 to 160.60 °C for neopentane: 1136.462 log10 pat = 3.901633 + 4.99118 10-4 T T (temperature in K and vapor pressure is in atmospheres). The critical temperature (Te) and critical pressure (Pc) of neopentane are 160.60°C and 31.57 atmospheres respectively. Using the information given above and the class notes, answer the questions #1. 1. The acentric factor w is used a characterization parameter in phase behavior calculations. Acentric factor is a measure of sphericity of a molecule. The definition of w is given below. psat @ =- log10 --1.0 prat is calculated at T/Tc= 0.7 Pc Here Pal is the vapor pressure of the component and, P. and T are critical properties of the component. Psat/P¢and T/Tc must be unitless (T and Tc must be in R or K). Calculate the acentric factor of neopentane (CSH12) using Antoine vapor pressure equation. (In data books, acentric factor for neopentane is given as 0.1961). 2. Determine the temperature at the normal boiling point of n-pentane (n-CSH12) using Antoine equation. (In data books, normal boiling point for n-pentane is given as 36.06°C)
Transcribed Image Text:Vapor pressure of a pure component (Psat) can be computed from the correlation equations. Beattie et al.(1951) gives the following equation between 50.00 to 160.60 °C for neopentane: 1136.462 log10 pat = 3.901633 + 4.99118 10-4 T T (temperature in K and vapor pressure is in atmospheres). The critical temperature (Te) and critical pressure (Pc) of neopentane are 160.60°C and 31.57 atmospheres respectively. Using the information given above and the class notes, answer the questions #1. 1. The acentric factor w is used a characterization parameter in phase behavior calculations. Acentric factor is a measure of sphericity of a molecule. The definition of w is given below. psat @ =- log10 --1.0 prat is calculated at T/Tc= 0.7 Pc Here Pal is the vapor pressure of the component and, P. and T are critical properties of the component. Psat/P¢and T/Tc must be unitless (T and Tc must be in R or K). Calculate the acentric factor of neopentane (CSH12) using Antoine vapor pressure equation. (In data books, acentric factor for neopentane is given as 0.1961). 2. Determine the temperature at the normal boiling point of n-pentane (n-CSH12) using Antoine equation. (In data books, normal boiling point for n-pentane is given as 36.06°C)
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