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(1 point) Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = = 4. The plaintext given by 11101101 = x0x1x2X3 X4 X5 X6 X 7 when encrypted by the LFSR produced the ciphertext 10000000 = YoY1Y2Y3Y3Y5Y6Y7. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent P3 = 0, P2 = 1,p1 = 0, po = 1).

(1 point) Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = = 4. The plaintext given by 11101101 = x0x1x2X3 X4 X5 X6 X 7 when encrypted by the LFSR produced the ciphertext 10000000 = YoY1Y2Y3Y3Y5Y6Y7. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent P3 = 0, P2 = 1,p1 = 0, po = 1).

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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(1 point) Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = = 4. The plaintext given by 11101101 = x0x1x2X3 X4 X5 X6 X 7 when encrypted by the LFSR produced the ciphertext 10000000 = YoY1Y2Y3Y3Y5Y6Y7. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent P3 = 0, P2 = 1,p1 = 0, po = 1).
Transcribed Image Text:(1 point) Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = = 4. The plaintext given by 11101101 = x0x1x2X3 X4 X5 X6 X 7 when encrypted by the LFSR produced the ciphertext 10000000 = YoY1Y2Y3Y3Y5Y6Y7. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent P3 = 0, P2 = 1,p1 = 0, po = 1).
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