**Problem 2:** Encrypt the message ATTACK using RSA with \( n = 43 \times 59 \) and \( e = 13 \). To convert letters, use: A is 00, B is 01, and so on. Show all steps.**Problem 3:** Find the private key for Problem 2 and decipher the message 20812182.(Note: There are no graphs or diagrams in the image.)

RSA stands for Rivest Shamir Adlemam.In RSA, the message is encrypted using public keys (e, n) and…

Answered: Encrypt message ATTACK using RSA with n…

Encrypt message ATTACK using RSA with n = 43.59 and e = 13. To Problem 2: convert letters use: A is 00, B is 01 and so on. Show all steps.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Cryptography

Cryptography is a term used in computer science to describe secure information and communication techniques that transform messages in difficult-to-decipher ways using mathematical concepts and a set of rule-based calculations known as algorithms.

Question

**Problem 2:** Encrypt the message ATTACK using RSA with \( n = 43 \times 59 \) and \( e = 13 \). To convert letters, use: A is 00, B is 01, and so on. Show all steps.

**Problem 3:** Find the private key for Problem 2 and decipher the message 20812182.

(Note: There are no graphs or diagrams in the image.)

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In an RSA system, the public key (n,e) of a given user is (323, 11). 1. What is the value of the exponent in the private key (n, d), of this user? 2. Suppose you want to send this user the message m = 45, write down the expression to generate the ciphertext for this message. 3. Suppose that your ciphertext, c, is 5, write down the expression to generate the plaintext matching this ciphertext. 4. Can you encrypt the message m=322 with this public key? O a. Yes O b. No
Alice and Bod have decided to use a symmetric encryption algorithm. They have some assumptions about their messages:- Messages only contain capital letters (i.e. A to Z)- The length of their shared key must be greater than or equal to the length of the plaintext- They assign each letter a number as follows: (A,0), (B,1), (C,2), (D,3),…, (Z,25)Their algorithm combines the key and the message using modular addition. The numerical values of corresponding message and key letters are added together, modulo 26. For example, if the plain text is “HELLO” and the key is “SECRET” then the encrypted message is calculated as following:Since the length of the plaintext is 5, we just need the first 5 letters of the key (i.e. “SECRE”), then for each letter, we should add corresponding letters in both the plaintext and the key modulo 26.Plaintext: H (7) E (4) L (11) L (11) O (14)Key: S (18) E (4) C (2) R (17) E(4)Cipher: Z (25) I (8) N(13) C(2) S (18) Write a program in Python, C/C++ or JavaScript to…
Perform Encryption and decryption using the RSA algorithm for the following: a. p=5; q = 11; e = 3; M = 12 b. p= 3; q = 17; e = 7; M = 2 c. p=7; q = 19; e = 11; M = 5 d. p= 7; q = 13; e = 11; M = 8 e. p= 13; q = 23; e = 5; M = 10
Let's encrypt a message using RSA: Choose p = 7 and q = 11, and then select e=13. a.Compute d b.Select plaintext message x=7. Produce the ciphertext y using the fast exponentiation algorithm. c. Decrypt the ciphertext (y) to verify that the initial plaintext (x) is produced. Again, please use the fast exponentiation algorithm.