In an RSA system, the public key (n,e) of a given user is (323, 11).1. What is the value of the exponent in the private key (n, d), of this user?2. Suppose you want to send this user the message m = 45, write down the expression to generate the ciphertext for this message.3. Suppose that your ciphertext, c, is 5, write down the expression to generate the plaintext matching this ciphertext.4. Can you encrypt the message m=322 with this public key?O a. YesO b. No

1. What is the value of the exponent in the private key(n,d) of the user? 2. Suppose you want to…

Answered: In an RSA system, the public key (n,e)…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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1 Consider the following encrypted message: YBAGRBO This message was encrypted using a standard transposition code with the following key: (3, 2, 7, 1, 6) The message is the name of a person. Decrypt this message below: 2. Create your own encrypted message using a standard transposition code. Show the work below, and write the key, the message, and the encrypted message. Key: Message: Encrypted message:
Bob sent Alice an encrypted message. The message consists of 3 words. In each word, Bob encoded the letters as follows: A = 01, B = 02, C = 03, ..., Z = 26. The he wrote the codes next to each other to form a number that represent the word. For example, the word "WE" is encoded as: 2305 since it consists of 2 letters W=23 and E=05. After encoding, Bob encrypted each encoded word with RSA using Alice public key(pq, e) where p=100000007, q=10000019, e=13. Alice received the following 3 encrypted words from Bob: 451095483713115 570203572152011 762324289903198 She used here RSA private key (d) to decrypt the message. The first word of the message that Bob sent was: WE.
Someone sends you a message of “4”. They also send you a copy of their message encrypted with their private key. The “signed”, or encrypted copy is “49”. Their public key is (exponent 23, clock 55). Show the math you can do to authenticate the message.
Messages are to be encoded using the RSA method, and the primes chosen are p “ 17 and q “ 19, so that n “ pq “ 323, and e “ 19. Thus, the public key is p323, 19q. (a) Show that the decryption exponent d (your private key) is 91.
I need help with the following problems in cryptography. A. Encrypt the message “Freedom” using the Playfair matrix M F H I K U N O P Q Z V W X Y E L A R G D S T B C T B. Construct the Playfair matrix with the keyword “LARGEST” and encrypt the message “Freedom” again. C. Compare the results obtained in A and B. How do you account for these results?
Alice sets up an RSA public/private key, but instead of using two primes, she chooses three primes p, q, and r and she uses n=pqr as her RSA-style modulus. She chooses an encryption exponent e and calculates a decryption exponent d. Encryption and Decryption are defined: C ≡ me mod n and m ≡ Cd mod n where C is the ciphertext corresponding to the message m. Decryption: de ≡ 1 mod φ(n) | Let p = 5, q = 7, r = 3, e = 11, and the decryption exponent d = -13. n = 105 & φ(n) = 48 Q: Alice upgrades to three primes that are each 200 digits long. How many digits does n have?
Suppose your RSA public key is PK: {n, e} = {13861, 37}. Your friend sends you a ciphertext C = 9908. But unfortunately you have forgotten your private key, now you have to crack it yourself.a) Write down a possible condition of factors p and q.p= q=b) What is your private key SK: {d}?d=c) What is the plaintext of your friend’s message?The plaintext M =d) Suppose the plaintext M is a 12-digit number consisting of a prefix “19” and 1234567890. What is the corresponding ciphertext? Since M is greater than n, you only need to encrypt four digits at a time. Ignore redundant zeros. e.g., 0001 = 1. The result should contain three integers.The ciphertext C0 =
Let's encrypt a message using RSA: Choose p = 7 and q = 11, and then select e=13. a.Compute d b.Select plaintext message x=7. Produce the ciphertext y using the fast exponentiation algorithm. c. Decrypt the ciphertext (y) to verify that the initial plaintext (x) is produced. Again, please use the fast exponentiation algorithm.

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