Suppose you call the function on the following linked list:headnull 202463451tail621755 16 mullWhat is the state of the linked list after the function call to grumbo(h,t)? You justhave to type out the numbers in the appropriate order seen in the linked list. }(1 of 5 parts) Consider the function grumbo below that takes head and tailpointers to doubly linked list.Node* grumbo (Node *h, Node *t) {Node *chumbo = t->next;Bfor (Node *j = t; j != h; j = j->prev) {while (j->value value) {if (chumbonullptr) chumbo = t;else chumbo - chumbo->prev;swap(chumbo->value, j->value);break;}if (chumbo == nullptr) chumbo = t;else chumbo chumbo->prev;swap(chumbo->value, h->value);return chumbo;

To solve the problem, we need to understand what the function grumbo does and then simulate its…

Answered: Suppose you call the function on the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write a function inde which returns the index (start from 1) of the occurrence of a given value. Use helper function. Two functions are enough.inde(1, [1,2,1,1,2,2,1]) → [1,3,4,7] Write a function nele which repeats each element in a list n times. Use helper function. Two functions only.nele([1,2],3) → [1,1,1,2,2,2] Write a function isfact to determine if a positive integer is a factorial number. Do not use any formula such as T(n)=n(n+1)/2. Do it in recursive fashion. Two functions are enough.isfact(120) → true
} (1 of 3 parts) Consider the function below that is given the head and tail pointers to a double linked list. bool patronum (Node ✶h, Node * t) { bool c = true; if (t nullptr) return true; Node* p = t; while (p != h) { Node* j = p; Node* r = p->prev; EXAM for (Node* r = p->prev; r != nullptr; r = r->prev) { if (j->value > r->value) { c = false; j = r; } swap(p->value, j->value); p = p->prev; return c;
How do you write a function that can reverse a linked-list?
I'm trying to delete a node after inputting data for 2-3 checks but the node I try to delete remains in the list. How do I fix my deleteCheck() function to run correctly with the rest of my code? Thank you. #include <stdio.h>#include <stdlib.h>// Austin Chong// The core concept of this assignment is to use a linked list in a C program.// 07 March 2020 struct checkNode{int checkNumber;char date[8];char paidTo[100];char description[100];double amount;struct checkNode *head;struct checkNode *next;}; struct checkNode *checkBook = NULL; /* Functions */ void addCheck(){int checkNumber;double amount;char temp;struct checkNode *newCheck = (struct checkNode*) malloc(sizeof(struct checkNode));printf("Please enter the check number: ");scanf("%d", &checkNumber);newCheck -> checkNumber = checkNumber;printf("Please enter the amount: ");scanf("%lf", &amount);newCheck -> amount = amount;printf("Please enter the date: ");scanf("%c", &temp);scanf("%[^\n]", newCheck ->…
SCHEME Sub All Write sub-all, which takes a list s, a list of old words, and a list of new words; the last two lists must be the same length. It returns a list with the elements of s, but with each word that occurs in the second argument replaced by the corresponding word of the third argument. You may use substitute in your solution. Assume that olds and news have no elements in common. (define (sub-all s olds news) 'YOUR-CODE-HERE )
3. Write the remove_evens() function that receives a list of integers as a parameter and returns a new list of integers containing only the odd numbers from the original list. Ex1) If n = [1, 2, 3, 4, 5, 6], remove_evens(n) returns [1, 3, 5]. Ex2) If n = [2, 4, 8], remov move_evens(n) returns [].
Fill up the blanks with the appropriate information. The property is the only one that is needed for the basic Linked List class to function.
Think about the following example: A computer program builds and modifies a linked list like follows:Normally, the program would keep tabs on two unique nodes, which are as follows: An explanation of how to use the null reference in the linked list's node in two common circumstances
scheme: Q9: Sub All Write sub-all, which takes a list s, a list of old words, and a list of new words; the last two lists must be the same length. It returns a list with the elements of s, but with each word that occurs in the second argument replaced by the corresponding word of the third argument. You may use substitute in your solution. Assume that olds and news have no elements in common. (define (sub-all s olds news) 'YOUR-CODE-HERE )

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