1 mole of steam is pressurized at 5 bar in a horizontal cylinder equipped with a frictionless piston. You need to cool the steam from 350 °C to 200 °C using a constant restraining force so that the piston can move due to work, but at constant pressure. You know the theoretical expected behavior (volume change) as you cool down the system. a. Calculate the mass of steam inside the cylinder. b. Calculate the heat removed Q from the steam to undergo the desired temperature change. c. Calculate the change in internal energy of the steam for the desired process. d. Calculate the work done by/on the steam using a closed system energy balance (AU=Q+W). e. Calculate the work done by/on the steam using the definition of work (W=-PAV), showing all necessary unit conversions. For the volume information, use specific volumes from the steam table.
1 mole of steam is pressurized at 5 bar in a horizontal cylinder equipped with a frictionless piston. You need to cool the steam from 350 °C to 200 °C using a constant restraining force so that the piston can move due to work, but at constant pressure. You know the theoretical expected behavior (volume change) as you cool down the system. a. Calculate the mass of steam inside the cylinder. b. Calculate the heat removed Q from the steam to undergo the desired temperature change. c. Calculate the change in internal energy of the steam for the desired process. d. Calculate the work done by/on the steam using a closed system energy balance (AU=Q+W). e. Calculate the work done by/on the steam using the definition of work (W=-PAV), showing all necessary unit conversions. For the volume information, use specific volumes from the steam table.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
Transcribed Image Text:TABLE B.7 Properties of Superheated Steam“
P(bar)
(Tsat. C)
Sat'd
Water
Temperature (C)→
50
Sat'd
Steam
75
100
150
200
250
300
350
2642
2481
0.0
2595
2689
2784
2880
2978
3077
3177
(-)
2446
2517
2589
2662
2736
2812
2890
2584.8
2438.0
3077
2812
0.1
191.8
2593
2640
2688
2783
2880
2977
3177
(45.8)
191.8
2444
2480
2516
2588
2661
2736
2890
V 0.00101
14.7
14.8
16.0
17.2
19.5
21.8
24.2
26.5
28.7
209.3
209.2
2683
2780
2586
3.89
2878
2660
4.35
2979
2735
4.83
0.5
340.6
2646.0
313.9
3076
3177
(81.3)
2484.0
3.24
2811
5.29
340.6
313.9
V 0.00103
2512
3.41
2889
5.75
0.00101
0.00103
2675.4
2506.1
1.69
209.3
209.2
314.0
313.9
0.00103
2776
2583
2875
2658
2.17
2975
2734
1.0
2676
417.5
417.5
V 0.00104
3074
3176
(99.6)
2507
2811
2889
0.00101
1.69
1.94
2.40
2.64
2.87
2961
2724
0.474
5.0
640.1
2747.5
209.7
314.3
419.4
632.2
2855
3065
3168
209.2
0.00101
631.6
0.00109
2803
0.522
(151.8)
639.6
2560.2
313.8
2643
2883
418.8
0.00104
V 0.00109
0.375
0.00103
0.425
0.571
762.6
761.5
V 0.00113
2943
2710
0.233
3159
2876
0.282
2776.2
210.1
314.7
632.5
2827
2621
10
419.7
3052
2582
0.194
209.1
0.00101
313.7
0.00103
631.4
0.00109
(179.9)
418.7
2794
0.00104
0.206
0.258
2797.2
2598.2
211.0
209.0
315.5
313.5
420.5
418.4
20
852.6
850.2
908.6
633.1
2902
3025
2774
0.125
3139
(212.4)
906.2
603.9
2679
2862
V 0.00118
À 1087.4
Û 1082.4
O 0.00125
0.09950
0.00101
0.00102
0.00104
0.00109
0.00116
0.111
0.139
212.7
317.1
422.0
853.4
848.8
1085.8
2962
2727
0.0588
40
2800.3
634.3
3095
(250.3)
417.8
0.00104
2601.3
208.6
313.0
630.0
1080.8
2829
0.0665
0.04975
0.00101
0.00102
0.00109
0.00115
0.00125
ÂĤ 1213.7
423.5
214.4
208.3
0.00101
635.6
629.1
0.00109
854.2
847.3
1085.8
1078.3
3046
2792
0.0422
60
2785.0
318.7
2885
(275.6)
1205.8
2590.4
312.6
417.3
2668
V 0.00132
0.0325
0.00103
0.00104
0.00115
0.00125
0.0361
2759.9
855.1
845.9
0.00115
80
1317.1
2990
216.1
208.1
320.3
425.0
636.8
1085.8
2787
2750
0.0299
(295.0)
1306.0
2571.7
312.3
416.7
628.2
1075.8
2593
V 0.00139
0.0235
0.00101
0.00102
0.00104
0.00109
0.00124
0.0243
2727.7
217.8
207.8
100
322.9
855.9
1085.8
1408.0
1393.5
V 0.00145
426.5
638.1
1343.4
2926
2702
0.0224
(311.0)
2547.3
311.7
416.1
627.3
844.4
1073.4
1329.4
0.0181
0.00101
0.00102
0.00104
0.00109
0.00115
0.00124
0.00140
ÂĤ 1611.0
222.1
207.0
0.00101
430.3
414.7
2695
2523
326.0
641.3
625.0
150
2615.0
858.1
1086.2
1338.2
1317.6
0.00138
(342.1)
1586.1
2459.9
310.7
0.00102
1067.7
0.00123
841.0
V 0.00166
0.0103
0.00104
0.00108
0.00114
0.0115
A 1826.5
Û 1785.7
O 0.00204
200
2418.4
2300.8
0.005875
434.0
413.2
226.4
330.0
644.5
860.4
1086.7
1334.3
1647.1
1613.7
0.00167
(365.7)
206.3
309.7
622.9
837.7
1062.2
1307.1
0.00100
0.00102
0.00103
0.00108
0.00114
0.00122
0.00136
2108
(374.15)(T.) 0 2037.8
V 0.00317
228.2
206.0
221.2(P.)
435.7
645.8
1635.5
1600.3
2108
331.7
861.4
1087.0
1332.8
2037.8
0.00317
309.2
412.8
622.0
836.3
1060.0
1302.9
0.00100
0.00102
0.00103
0.00108
0.00114
0.00122
0.00135
0.00163
250
230.7
334.0
437.8
647.7
862.8
1087.5
1331.1
1625.0
(-)
205.7
1297.5
0.00135
308.7
412.1
0.00103
620.8
834.4
1057.0
1585.0
0.00100
0.00101
0.00108
0.00113
0.00122
0.00160
235.0
205.0
0.0009990
338.1
307.7
0.00101
650.9
618.7
0.00107
865.2
831.3
1088.4
1052.1
1609.9
1563.3
300
441.6
1328.7
(-)
1288.7
0.00133
410.8
0.00103
0.00113
0.00121
0.00155
1576.3
1504.1
0.00144
251.9
354.2
456.8
664.1
611.0
500
875.4
1093.6
1323.7
(-)
202.4
304.0
405.8
819.7
1034.3
1259.3
0.0009911
0.00100
0.00102
0.00106
0.00111
0.00119
0.00129
698.0
594.4
0.00104
1550.5
1419.0
1000
293.9
196.5
394.3
495.1
395.1
903.5
795.3
1113.0
1328.7
1207.1
0.00122
(-)
295.7
0.0009852
999.0
0.0009737
0.001000
0.00108
0.00114
0.00131
" Adapted from R. W. Haywood, Thermodynamic Tables in SI (Metric) Units, Cambridge University Press, London, 1968.
Water is a liquid in the enclosed region between 50°C and 350°C. ÂĤ = specific enthalpy (kJ/kg), Û = specific internal energy
(kJ/kg), V = specific volume (m³/kg). Note: kJ/kg × 0.4303 = Btu/lb.
(continued)
•..
||| ||| ||||||
Transcribed Image Text:1 mole of steam is pressurized at 5 bar in a horizontal cylinder equipped with a frictionless piston. You need to cool the steam from 350 °C to 200 °C using a constant restraining force so
that the piston can move due to work, but at constant pressure. You know the theoretical expected behavior (volume change) as you cool down the system.
a. Calculate the mass of steam inside the cylinder.
b. Calculate the heat removed Q from the steam to undergo the desired temperature change.
c. Calculate the change in internal energy of the steam for the desired process.
d. Calculate the work done by/on the steam using a closed system energy balance (AU=Q+W).
e. Calculate the work done by/on the steam using the definition of work (W=-PAV), showing all necessary unit conversions. For the volume information, use specific volumes from the
steam table.
Given: 1 bar = 105 N/m2, Q = AH, Q = AU, AĤ = AÛ + PAV, table B.7 in kJ/kg and m3/kg.
%3D
%3D
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