1 mol N20(9) and 2 mol NO(g); Match the words in the left column to the appropriate blanks in the sentences on the right. Reset H more complex will have the higher standard molecules have more vibrational entropy at 25 °C. degrees of freedom This can best be explained because the gas phase has more degrees of freedom associated with movement 2 mol NO(g) a greater number of particles has a greater number of microstates available liquid or aqueous phases have more degrees of freedom associated with movement fewer particles occupy a smaller volume 1 mol N½0(g)

1 mol N20(9) and 2 mol NO(g); Match the words in the left column to the appropriate blanks in the sentences on the right. Reset H more complex will have the higher standard molecules have more vibrational entropy at 25 °C. degrees of freedom This can best be explained because the gas phase has more degrees of freedom associated with movement 2 mol NO(g) a greater number of particles has a greater number of microstates available liquid or aqueous phases have more degrees of freedom associated with movement fewer particles occupy a smaller volume 1 mol N½0(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Discuss the diagram of the molar Gibbs free energy (or chemical potential) versus temperaturebelow for a pure substance. Why are there three curves? Why do they slope downward? Does thegraph identify any interesting temperatures? Are some segmentsof the curves more important/interesting than others? Feel free to redraw and label the diagram.
20. Although the standard molar entropy, (AS), of a lot of chemicals are available, (AS) of most chemicals, especially the newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar entropy of a few compounds. Trinitrotoluene (C₂H5N3Q6), abbreviated as TNT is one of the most famous explosives. Please use the above table and the standard entropy of reaction of the detonation reaction of TNT to find the Sº of TNT. 0 2 C₂H5N306(5) → 3 N₂(g) + 5 H₂O(g) + 7 CO(g) + 7 C(graphite,s) ASrxn = 488.9 J/K so of TNT = Substance So mol K Substance sº (mlk) J mol K CO(g) 197.9 CO₂(g) 213.6 H₂O(g) 188.83 MgO(s) 69.91 26.8 0₂(g) H₂O(1) Mg(OH)2 (s) C(graphite, s) 63.24 205.0 5.69 N₂(g) 191.50
5
Ip acellus_engine.html?ClassID=D1653724337# Calculate the entropy of the phase change of uranium hexafluoride from gas to solid. UF6(g) → UF6(s) Substance S° (J/mol-K) UF (s) UF (g) ASiep = [ ? ] J/mol - K 228 380 Enter either a + or - sign AND the magnitude in your answer. Enter
Consider the reaction: 2BrF3(g) → Br2(g) + 3F2 (g) Using standard thermodynamic data at 298 K, calculate the free energy change when 2.40 moles of BrF3 (g) react at standard conditions. Substance AG (kJ/mol) BrF3 (9) Br₂ (9) F₂ (g) AGTER Submit Answer kj -229.4 3.1 0.0 Retry Entire Group 9 more group attempts remaining
1)spontaneous or non spontaneous 2) the change in Gibbs free energy is negative or the change in Gibbs free energy is positive 3)positive or negative
You are boiling 2 liters of water on the stove. You forget about it and return later to find that there is only 0.5 liters of water left. Over this time what happened to the temperature of the water and the entropy of the room you’re boiling water in?
22. Although the standard molar entropy, (AS), of a lot of chemicals are available, (AS) of most chemicals, especially the newly discovered chemicals are NOT available, you have to calculate the values of the (AS). The following table lists the standard molar entropy of a few compounds. The following reaction occurs when sucrose (cane sugar) is metabolized by the body. 0 C12H22O11(s) + 12 O₂(g) → 12 CO₂(g) + 11 H₂O(1) ASrxn = 512.01 J/K What is the standard molar entropy, 50 of sucrose solid? Substance So J mol K Substance sº G (molk) CO(g) 197.9 CO₂(g) 213.6 H₂O(g) MgO(s) 188.83 26.8 69.91 0₂(g) H₂O(1) Mg(OH)2 (s) C(graphite, s) 63.24 205.0 5.69 J mol K N₂(g) 191.50
Fill in the blanks below, with A, B, C or D: A В Structure expected to have the highest molar entropy and structure is expected to have the lowest molar entropy.
8. You have discovered a new polymer. A monomer is shown below. To better understand its behavior you calculate its theoretical entropy. With careful measurements you find that it can be in 3 positions around the 1st bond in the chain, 2 around the 2nd bond, 1 around the 3rd bond and 3 around the 4th bond. Further, the ring can be in 4 different positions. What is the entropy in units of KB?