-1+ <+16y=0 d²y dy dt² dt d²y dy e)2- + dt² dt d²y +9y=0 dt² i) +16y=1/ cos 4t d²y dt² po -2+ +5. + y = 5 cos 4 (t) +10y = 0 12 t d²y dt2 b) d))2 dy dt dt² f) h) + y = 5 cos 2(t) dt² dt² dy dt +3y= cos 1lt + 11y = cos 3t +10y = 0 + 4y = cos 4t
-1+ <+16y=0 d²y dy dt² dt d²y dy e)2- + dt² dt d²y +9y=0 dt² i) +16y=1/ cos 4t d²y dt² po -2+ +5. + y = 5 cos 4 (t) +10y = 0 12 t d²y dt2 b) d))2 dy dt dt² f) h) + y = 5 cos 2(t) dt² dt² dy dt +3y= cos 1lt + 11y = cos 3t +10y = 0 + 4y = cos 4t
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Math the follow with short explanation why . ( About a sentence )

Transcribed Image Text:-2+
-14
g)
-2+
i)
d²y
dt²
d²y
dt²
+ 16y=0
dy
dt
dt2
+5
d²y dy
+
dt²
dt
+9y = 0
+ y = 5 cos 4 (t)
+10y = 0
+ 16y=
Jums
pwwwww
1
cos 4t
T
8
dy
dt
d²y
dt2
d))2-
f)
h)
+ y = 5 cos 2(t)
dt²
dt²
d²y
dt²
+10y = 0
dt
+ 3y = cos 1lt
+ 11y = cos 3t
+ 4y =
1/1/20
cos 4t
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