1) In Figure, a block with mass m = 1 kg is released from height h,friction until it reaches the path with first length d,= 2 m, where the friction force between B andC is f = 8 N, and until it reaches the path, where the friction force between E and F is f, = 6 NThe height is h, = 1 m, and second horizontal length is d, = 1 m. The block continues its motiorafter the point F.(a) Find the velocity at the point A.(b) Find the velocity at the point D.(c) Find the height h if the velocity of m is vp= 8 m/s at the point F.(sin60=0.86 g=9.8 m/s²)12 m. Its path is withourmd,=1 mh, = 12 mD60°%3DEd;=2 mh,=1 mА В

Given that: Mass of the block, m=1 kgInitial height, h1=12 mPath length between B to C, d1=12…

Answered: 1 kg is released from height h, = 12 m.…

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