) A man pushes a 20.0 kg lawn mower with a force of 80.0 N directed along the handle, which is inclined at 30.0° to the horizontal as shown in the figure below. (a) If he moves at constant velocity, what is the impeding force due to the ground? (b) What force along the handle would produce an acceleration of 1.25 m/s' given the same impeding force? I need to show all work draw picture
) A man pushes a 20.0 kg lawn mower with a force of 80.0 N directed along the handle, which is inclined at 30.0° to the horizontal as shown in the figure below. (a) If he moves at constant velocity, what is the impeding force due to the ground? (b) What force along the handle would produce an acceleration of 1.25 m/s' given the same impeding force? I need to show all work draw picture
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1) A man pushes a 20.0 kg lawn mower with a force of 80.0 N directed along the handle, which is inclined at 30.0° to the horizontal as shown in the figure below. (a) If he moves at constant velocity, what is the impeding force due to the ground? (b) What force along the handle would produce an acceleration of 1.25 m/s' given the same impeding force?
I need to show all work draw picture

Transcribed Image Text:**Physics Problem Flow Chart**
1. **Draw a picture**
- Label which directions are positive (x- and y-), and label relevant quantities on the diagram.
2. **Draw a second picture…**
- If you have BEFORE/AFTER situations, force additions, vector component diagrams.
3. **Identify explicitly given values**
- Write all given actual numbers in terms of variables. For previously calculated values, use values before rounding for sig figs.
4. **Identify implicitly given values**
- Wording that implies specific values, e.g., “at rest,” “comes to a stop,” “dropped,” “smooth surface,” “constant velocity.”
5. **Identify required quantity and type of problem**
- Look for keywords like “when,” “how far,” “how fast,” etc. Get the type of problem from quantities given/sought.
6. **Calculate/convert easily derived quantities**
- For example, the x- and y-components of velocity/force vectors, or the force of gravity given the mass.
7. **Find relevant equation(s)**
- One that links the given quantities to the quantity you need to find.
8. **Find a second equation…**
- If you’re missing a quantity needed to use an equation. Draw up a plan on how to link the equations & quantities.
9. **Solve for the quantity without using numbers**
- First, cancel any quantities that are zero. Use algebra to isolate the quantity you need on one side of the equals sign. Check with dimensional analysis.
10. **Sub in numbers on paper**
- Make sure units of each number are correct before you substitute in values into the equations.
11. **Use calculator to find value**
- Use as few presses of the “=” or “ENTER” button as possible. Keep extra sig figs until next step.
12. **Write conclusion statement with correct sig figs**
- In plain English with correct units.

Transcribed Image Text:**Problem Description:**
1) A man pushes a 20.0 kg lawn mower with a force of 80.0 N directed along the handle, which is inclined at 30.0° to the horizontal as shown in the figure below.
**Questions:**
(a) If he moves at constant velocity, what is the impeding force due to the ground?
(b) What force along the handle would produce an acceleration of 1.25 m/s² given the same impeding force?
**Diagram Explanation:**
The figure illustrates a lawn mower being pushed with a force applied along a handle that is inclined at 30.0° to the horizontal. The lawn mower is depicted as a rectangle with wheels on a flat surface. The force is shown as an arrow along the handle, indicating the direction of the push. The angle between the handle and the horizontal is clearly marked as 30.0°. The setup implies that the force has both horizontal and vertical components due to the inclination of the handle.
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