1 in. -10 in.- t2 in.- a t1 in. 10 in. P kips Р x ft- 3 ft In In tl in. Determine the maximum stress in ksi from the bending moment on the beam in cross-section n-n if a force of P = 45.9 kip is applied to the end. Use the following dimensions: t₁ = 0.661 in t₂ = 0.386 in x= 1.64 ft Calculate your answer to four significant figures.

1 in. -10 in.- t2 in.- a t1 in. 10 in. P kips Р x ft- 3 ft In In tl in. Determine the maximum stress in ksi from the bending moment on the beam in cross-section n-n if a force of P = 45.9 kip is applied to the end. Use the following dimensions: t₁ = 0.661 in t₂ = 0.386 in x= 1.64 ft Calculate your answer to four significant figures.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter6: Stresses In Beams (advanced Topics)

Section: Chapter Questions

Problem 6.5.6P: The Z-section of Example D-7 is subjected to M = 5 kN · m, as shown. Determine the orientation of...

See similar textbooks

Similar questions

4
a. the maximum tension bending stress at any location along the beam b. Determine the maximum compression bending stress at any location along the beam
a. the maximum tension bending stress at any location along the beam b. Determine the maximum compression bending stress at any location along the beam
Find the second moment of area, the location of the neutral axis, and the distances from the neutral axis to the top and bottom surfaces. Consider that the section is transmitting a positive bending moment about the z axis, Mz, where M₂ = 10 kip-in if the dimensions of the section are given in ips units, or M₂ = 1.13 kN·m if the dimensions are in Sl units. Determine the resulting stresses at the top and bottom surfaces and at every abrupt change in the cross section. From the figure, с - 12.5 B A y I 50 100 75 12.5- 12.5 25 D 100 The area is determined to be 3750 mm² The distances from the neutral axis to the top and bottom surfaces are determined to be 57.292 The second moment of area is determined to be 4.293 x 106 mm4. mm and 42.708 ✪ mm.
Find the second moment of area, the location of the neutral axis, and the distances from the neutral axis to the top and bottom surfaces. Consider that the section is transmitting a positive bending moment about the z axis, Mz, where M₂ = 10 kip-in if the dimensions of the section are given in ips units, or M₂ = 1.13 kN·m if the dimensions are in Sl units. Determine the resulting stresses at the top and bottom surfaces and at every abrupt change in the cross section. From the figure Z 1 in 112 in y in → ← ¹ in 12 in D C B A ++ in The area is determined to be 2.0625 in². The distances from the neutral axis to the top and bottom surfaces are determined to be 0.858 x in and The second moment of area is determined to be 0.447 in 4. 1.017 xin.
The simply supported joist is used in the construction of a floor for a building. In order to keep the floor low with respect to the sill beams C and D, the ends of the joists are notched as shown. If the allowable shear stress is tallow = 350 psi and the allowable bending stress is sallow = 1500 psi, determine the height h that will cause the beam to reach both allowable stresses at the same time. Also, what load P causes this to happen? Neglect the stressconcentration at the notch.
Below Figure shows the section of an angle purlin. A bending moment of 60 5 kN.m is applied to the purlin in a plane at an angle of 30 deg to the vertical y axis. If the sense of the bending moment is such that both its components Mx and My produce tension in the positive xy quadrant, calculate the maximum direct stress in the purlin, stating clearly the point at which it acts. * 100 mm BỊ 10mm 30° C ID 10mm 57 MPa. 89 MPa. Non Above 72 MPa. 125mm
q3
The simply supported beam is subjected to the force F = 700 N and the uniform distributed load with intensity w = 150 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(r) and M(x). Take a = 0 at point A. 19 F a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 m 2.6 m 3.12 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: v(x)- N and M(x)= N-m. In section CD: V(x)- N and M(x)= N-m. A
Q2/ For simple supported bom * The cross section al area is B * The maximum bending equal to M momnt * The maximum sheur force qual to V an expression for the maaimum beneding and maximum shear stress Derive stress
Determine the moment M that must be applied to the beam in order to create amaximum stress of 90 MPa. Also sketch the stress distribution acting over the cross section.
Determine the average shear stress developed in the nails within region AB of the beam. The nails are located on each side of the beam and are space 100 mm apart. Each nail has a diameter of 4 mm. Take P = 2kN. = Hint: Think carefully about the number of nails transferring shear stress from board-to-board. 2 kN/m A B -1.5 m 1.5 m 100 mm + 20 mm 40 mm 200 mm 20 mm 200 mm