(1) f(x) = sin (5x + 6) (3) f(x) = sin(x-³) (2) f(x) = sin (3x4 + 2) (4) f(x) = cos (4+ 3x)

Q: 4 If f(x) = 4 + + find f'(x). | x2 Preview Find f'(3). Preview

A: Given that the function   f(x) = 4+5x+4x2 To find f'(x) and f'(3)

Q: Let ƒ'(x) = ƒ'(2) = f(x) = (x³ + 4x + 8) ²

A: f(x)=(x3+4x+8)2 d dx(xn)=nxn-1d dx(constant)=0

Q: Let f(x)=4x^(3)- 8 Find f '(4)

A:

Q: = (1) cotr 1+csc.x

A: We will find the required.

Q: Find f. f'(x)  = x-1/3    ,f(1)  =1, f(-1)  = -1

A: To find f(x) we integrate f'(x) C=integrating constant

Q: f'(x) = +6) ¹¹(™). Find f'(x). Let f(x) = (x³ + 6)¹(x).

A:

Q: Differentiate. f(x) = 7e³x f'(x) =

A: we need to find out the derivative of the given function.

Q: Identify the open interval(s) where f is concave up. [A] (-∞, -1) [B] (-∞, -3) U (-1,2) [C] (-1,00)…

A: for concave up , f'(x) is increasing For given graph , f'(x) is increasing on

Q: Find f'(x) if f(x) = 1 (x+csda4+10))³

A: *concept:- cscx = 1/sinx. d/dx (sinx) = cosx. d/dx (x^{n}) = nx^{(n-1)}

Q: Find f ' x if f x =sqrt ( x2 + 1)

A:

Q: Find f x) and f xof fCx) = 11x³

A:

Q: F’(-4)=

A:

Q: determine f given f' and a point which statify f. f'(X)= 4x3-3x2+2x (3,80)

A: To determine f given f' and a point which statify f.   f'(X)= 4x3-3x2+2x (3,80)

Q: f'(x) = Differentiate the function f(x)=x197 +19.7.

A: Explanation of the answer is as follows

Q: find f 'a  f (x)= sqrt(1-2x)

A:

Q: If f(x) = 7/¤(x – - 3/a + 5), find f'(9).

A: Given : f(x)=7x x3-3x+5 We have to find f'(9)

Q: Let f'(x) = 8. Find f(x) when f(2) = 7. f(x) =

A:

Q: Find the derivative f(x)= In(ex+9)

A: find the derivative

Q: Let f(x)=sqrt[x]+1/sqrtx what is f'(4)

A:

Q: Find the function f that satisfies f '(x) = 3x^2- 8x+ 2 and f(1) = 6.

A:

Q: Find f'(x) for the function. RM) = 7x(17x* + ) x + 1 f'(x) = %3D

A:

Q: Differentiate f (x)  = eex

A: f(x)=eex

Q: Find f. f '(x) = 1 + 3(sqrt(x)),    f(4) = 22 f(x) =

A:

Q: Let f(x) = Find f' (z). (z² 4) f(x) =|

A:

Q: Determine f '(x)

A: Given:The function is

Q: find f'(x) when f(x)=-3/x2

A: Given:- f(x)=-3x2 To find:- f'(x)

Q: f(z) %3D 8+12 f'(z) = Find f'(5). f'(5) =

A: