Differentiate. F(x)= F'(x) = e3x 9

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Differentiate.

\[ F(x) = \frac{e^{3x}}{x^9} \]

\[ F'(x) = \_\_\_\_\_ \]

Explanation:

The problem is asking for the derivative of the function \( F(x) \). The function is given as a quotient of \( e^{3x} \) and \( x^9 \). To find \( F'(x) \), the derivative, you would typically apply the quotient rule, which is:

If \( u(x) \) and \( v(x) \) are differentiable functions, then the derivative of the quotient \( \frac{u(x)}{v(x)} \) is:

\[ \left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2} \]

Here, \( u(x) = e^{3x} \) and \( v(x) = x^9 \). You will need to find \( u'(x) \) and \( v'(x) \) and apply the quotient rule accordingly.
Transcribed Image Text:Differentiate. \[ F(x) = \frac{e^{3x}}{x^9} \] \[ F'(x) = \_\_\_\_\_ \] Explanation: The problem is asking for the derivative of the function \( F(x) \). The function is given as a quotient of \( e^{3x} \) and \( x^9 \). To find \( F'(x) \), the derivative, you would typically apply the quotient rule, which is: If \( u(x) \) and \( v(x) \) are differentiable functions, then the derivative of the quotient \( \frac{u(x)}{v(x)} \) is: \[ \left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2} \] Here, \( u(x) = e^{3x} \) and \( v(x) = x^9 \). You will need to find \( u'(x) \) and \( v'(x) \) and apply the quotient rule accordingly.
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