1 Find the cross product uxv. U=it 3-k, v=2i-j tk 2. Find the area of AABC and the equations of the plane through A, B, C. Use Vector methods A(1,2,3), B(3,1,2), C (2,3,-1) 3. Find in each case the perpendicular distance between the given lines X-1 y+1 2-1 xta y-1 = 3 , 2 S 4 3 2+1 -2 4- Use vector methods to find, in each case, the equations in symmetric form of the line through the given point P and parallel to the two given planes. P(-1, 3, 2), 3x-2y + 42 +2 = 0, 2x+y-z = 0 3. Find in each case equations in symmetric form of the line of intersection of the given planes. Use vector method of vector products 2(x-1)+3(y+1) - 4 (2-2)=0 3(x-1)-4(y11) +2 (2-2)=0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1 Find the cross product uxv.
U=it 3-k, v=2i-j tk
2. Find the area of AABC and the equations of the plane through
A, B, C. Use
Vector methods
A(1,2,3), B(3,1,2), C (2,3,-1)
3. Find in each case the perpendicular distance between the given
lines
X-1
y+1
2-1
xta
y-1
=
3
,
2
S
4
3
2+1
-2
4- Use
vector methods to find, in each case,
the
equations in
symmetric form of the line through the given point P and parallel
to the two given planes.
P(-1, 3, 2), 3x-2y + 42 +2 = 0, 2x+y-z = 0
3. Find in each case equations in symmetric form of the line of
intersection of the given planes. Use vector method of vector
products
2(x-1)+3(y+1) - 4 (2-2)=0
3(x-1)-4(y11) +2 (2-2)=0
Transcribed Image Text:1 Find the cross product uxv. U=it 3-k, v=2i-j tk 2. Find the area of AABC and the equations of the plane through A, B, C. Use Vector methods A(1,2,3), B(3,1,2), C (2,3,-1) 3. Find in each case the perpendicular distance between the given lines X-1 y+1 2-1 xta y-1 = 3 , 2 S 4 3 2+1 -2 4- Use vector methods to find, in each case, the equations in symmetric form of the line through the given point P and parallel to the two given planes. P(-1, 3, 2), 3x-2y + 42 +2 = 0, 2x+y-z = 0 3. Find in each case equations in symmetric form of the line of intersection of the given planes. Use vector method of vector products 2(x-1)+3(y+1) - 4 (2-2)=0 3(x-1)-4(y11) +2 (2-2)=0
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