3. Find an equation of the plane passing through the points (1, 2, -6), (2, 3, -2), and (-1, 4, 8). Use vector operations.

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**Problem 3: Finding the Equation of a Plane Using Vector Operations**

**Given:**
Find an equation of the plane passing through the points \((1, 2, -6)\), \((2, 3, -2)\), and \((-1, 4, 8)\). Use vector operations.

**Solution Outline:**

To find the equation of a plane passing through three points \((x_1, y_1, z_1)\), \((x_2, y_2, z_2)\), and \((x_3, y_3, z_3)\):
1. Find two vectors that lie in the plane.
2. Compute the cross product of these vectors to find a normal vector to the plane.
3. Use the normal vector and one of the points to write the equation of the plane in the form \(Ax + By + Cz = D\).

**Steps:**

1. **Identify the points:**
   Points: \(A = (1, 2, -6)\), \(B = (2, 3, -2)\), \(C = (-1, 4, 8)\).

2. **Find two vectors that lie in the plane:**
   Let \(\vec{AB}\) and \(\vec{AC}\) be the two vectors.

   \[
   \vec{AB} = B - A = (2 - 1, 3 - 2, -2 + 6) = (1, 1, 4)
   \]

   \[
   \vec{AC} = C - A = (-1 - 1, 4 - 2, 8 + 6) = (-2, 2, 14)
   \]

3. **Compute the cross product of \(\vec{AB}\) and \(\vec{AC}\) to find the normal vector \(\vec{n}\):**

   \[
   \vec{n} = \vec{AB} \times \vec{AC} =
   \begin{vmatrix}
   \mathbf{i} & \mathbf{j} & \mathbf{k} \\
   1 & 1 & 4 \\
   -2 & 2 & 14
   \end{vmatrix}
   \]

   This gives us:

   \[
   \vec{n} = (1
Transcribed Image Text:**Problem 3: Finding the Equation of a Plane Using Vector Operations** **Given:** Find an equation of the plane passing through the points \((1, 2, -6)\), \((2, 3, -2)\), and \((-1, 4, 8)\). Use vector operations. **Solution Outline:** To find the equation of a plane passing through three points \((x_1, y_1, z_1)\), \((x_2, y_2, z_2)\), and \((x_3, y_3, z_3)\): 1. Find two vectors that lie in the plane. 2. Compute the cross product of these vectors to find a normal vector to the plane. 3. Use the normal vector and one of the points to write the equation of the plane in the form \(Ax + By + Cz = D\). **Steps:** 1. **Identify the points:** Points: \(A = (1, 2, -6)\), \(B = (2, 3, -2)\), \(C = (-1, 4, 8)\). 2. **Find two vectors that lie in the plane:** Let \(\vec{AB}\) and \(\vec{AC}\) be the two vectors. \[ \vec{AB} = B - A = (2 - 1, 3 - 2, -2 + 6) = (1, 1, 4) \] \[ \vec{AC} = C - A = (-1 - 1, 4 - 2, 8 + 6) = (-2, 2, 14) \] 3. **Compute the cross product of \(\vec{AB}\) and \(\vec{AC}\) to find the normal vector \(\vec{n}\):** \[ \vec{n} = \vec{AB} \times \vec{AC} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 1 & 1 & 4 \\ -2 & 2 & 14 \end{vmatrix} \] This gives us: \[ \vec{n} = (1
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