1 Ca(OH)2 +2 HBr - 1 CaBr2 + 2 H2O Concentration of base 2.5 M Final buret reading 16.8 mL Initial buret reading 10.6 mL Volume of base used (in mL) mL Volume of base used (in L) L Volume of acid used (in mL) 30 mL Volume of acid used (in L) Concentration of acid unknown Step1: determine the number of moles of base reacted. Put this in BCA table Step2: Use BCA table to calculate the number of moles of acid reacted Step3: calculate the concentration of the acid M of acid (round to 2 decimal places)

1 Ca(OH)2 +2 HBr - 1 CaBr2 + 2 H2O Concentration of base 2.5 M Final buret reading 16.8 mL Initial buret reading 10.6 mL Volume of base used (in mL) mL Volume of base used (in L) L Volume of acid used (in mL) 30 mL Volume of acid used (in L) Concentration of acid unknown Step1: determine the number of moles of base reacted. Put this in BCA table Step2: Use BCA table to calculate the number of moles of acid reacted Step3: calculate the concentration of the acid M of acid (round to 2 decimal places)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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If 21 mL of 3.2 x 10–5 M magnesium chloride and 15 mL of 1.5 x 10–4 M sodium fluoride are mixed, what are the concentrations of magnesium ion, chloride ion, sodium ion, and fluoride ion after mixing? Some choices may be used more than once, and keep an extra sig fig. Question 9 options: chloride ion sodium ion magnesium ion fluoride ion 1. 1.87 x 10–5 M 2. 3.73 x 10–5 M 3. 6.25 x 10–5 M 4. 1.25 x 10–4 M 5. 1.50 x 10–4 M 6. 3.20 x 10–5 M 7. 1.50 x 10–4 M Answer and Explain
Referring back to the titration experiments you completed this semester for Experiment #6 (Volumetric Analysis), suppose you were to use 0.50 M potassium hydroxide as the base instead of 0.50 M sodium hydroxide. How would this affect the results of the experiment? O Less base would be required because the stoichiometry of potassium hydroxide reacting with hydrochloric acid is different. The results would be the same because the molarity of the base is unchanged O The results would change because potassium hydroxide is elementally different from sodium hydroxide. O Potassium hydroxide would react with the hydrochloric acid at a different pH.
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Write the balcned molecular equations 1. Cu (s) + 6M HCL (aq) 2. Fe (s) + 6M HCL (aq) 3. Mg (s) + 6M HCL (aq) 4. Zn (s) + 6M HCL (aq)
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Na,CO3(ag) + CaCl2(aq) 2 NaCl(aq) + CACO3(s) Order the steps required to predict the volume (in mL) of 0.100 M sodium carbonate needed to produce 1.00 g of calcium carbonate. There is an excess of calcium chloride. Step 1 Choose match Convert the volume of sodium carbonate solution required from liters to milliliters Compute the volume of sodium carbonate solution required v Compare moles of caicium carbenate to moles of sodium carbonate based on balanced equation to calcuiate moles of sodium carbonate reauired Convert mass of calcium carbonate to moles of calcium carbonate Step 3 Choose match Step 4 Choose match
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Listen Which equation below correctly describes the formation of a solution of calcium chloride in water? A) CaCl2(s) + H₂O (1)→ Ca2+ (aq) + Cl₂ (aq) B) CaCl2(s) + H₂0 (1)→ Ca²+(aq) +2Cl¯(aq) OC) OD) CaCl2(s) + H₂O (1) CaCl₂(aq) CaCl2(s) + H₂O (1)→ CaCl2(s)
nese answers will not be recorded ot pt pt 1 pt It is desired to prepare 600 mL of 0.250 normal Ba(OH)2 for use in the reaction: 2 HNO3 + Ba(OH)₂ - How many grams of Ba(OH)₂ are needed? Submit Answer →→→→Ba (NO3)2 + 2 H₂O Visited Try Another Version g 10 item attempts remaining
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