How many mL of water must be added to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has concentration of 6.00 M? **Problem: Dilution of Copper(II) Sulfate Solution**How many mL of *water must be added* to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has a concentration of 6.00 M?**Options:**- ○ 135 mL- ○ 4.67 mL- ○ 139 mL- ○ 16.8 mL**Instructions:**To solve this problem, apply the dilution equation:\[ C_1V_1 = C_2V_2 \]Where:- \( C_1 \) = concentration of the initial solution (stock solution) = 6.00 M- \( V_1 \) = volume of the initial solution to be found- \( C_2 \) = concentration of the diluted solution = 0.200 M- \( V_2 \) = final total volume of the solution = 140 mLCalculate \( V_1 \) and subtract from 140 mL to find the amount of water to be added.

Given Initial Concentration ( M1 ) = 6.00 M Final Molarity ( M2 ) = 0.200 M Final Volume ( V2 )…

How many mL of water must be added to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has concentration of 6.00 M? O 135 mL O 4.67 mL O 139 mL 16.8 mL

How many mL of water must be added to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has concentration of 6.00 M? O 135 mL O 4.67 mL O 139 mL 16.8 mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

How many mL of water must be added to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has concentration of 6.00 M?

**Problem: Dilution of Copper(II) Sulfate Solution**

How many mL of *water must be added* to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has a concentration of 6.00 M?

**Options:**

- ○ 135 mL
- ○ 4.67 mL
- ○ 139 mL
- ○ 16.8 mL

**Instructions:**

To solve this problem, apply the dilution equation:
\[ C_1V_1 = C_2V_2 \]

Where:
- \( C_1 \) = concentration of the initial solution (stock solution) = 6.00 M
- \( V_1 \) = volume of the initial solution to be found
- \( C_2 \) = concentration of the diluted solution = 0.200 M
- \( V_2 \) = final total volume of the solution = 140 mL

Calculate \( V_1 \) and subtract from 140 mL to find the amount of water to be added.

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