How many mL of water must be added to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has concentration of 6.00 M? O 135 mL O 4.67 mL O 139 mL 16.8 mL
How many mL of water must be added to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has concentration of 6.00 M? O 135 mL O 4.67 mL O 139 mL 16.8 mL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How many mL of water must be added to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has concentration of 6.00 M?
![**Problem: Dilution of Copper(II) Sulfate Solution**
How many mL of *water must be added* to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has a concentration of 6.00 M?
**Options:**
- ○ 135 mL
- ○ 4.67 mL
- ○ 139 mL
- ○ 16.8 mL
**Instructions:**
To solve this problem, apply the dilution equation:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) = concentration of the initial solution (stock solution) = 6.00 M
- \( V_1 \) = volume of the initial solution to be found
- \( C_2 \) = concentration of the diluted solution = 0.200 M
- \( V_2 \) = final total volume of the solution = 140 mL
Calculate \( V_1 \) and subtract from 140 mL to find the amount of water to be added.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F840f535b-f075-49f5-9fe8-c5a30f6f8dd7%2Fc5f659bc-87d1-418e-ab4d-57d4f6d5065b%2Fh5k137_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem: Dilution of Copper(II) Sulfate Solution**
How many mL of *water must be added* to create a total volume of 140. mL of a 0.200 M solution of copper(II) sulfate if the stock solution has a concentration of 6.00 M?
**Options:**
- ○ 135 mL
- ○ 4.67 mL
- ○ 139 mL
- ○ 16.8 mL
**Instructions:**
To solve this problem, apply the dilution equation:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) = concentration of the initial solution (stock solution) = 6.00 M
- \( V_1 \) = volume of the initial solution to be found
- \( C_2 \) = concentration of the diluted solution = 0.200 M
- \( V_2 \) = final total volume of the solution = 140 mL
Calculate \( V_1 \) and subtract from 140 mL to find the amount of water to be added.
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