1 A student pilot taxing a Cessna 172-Skyhawk is brought to a full stop with a total distance of four hundred fifty meters from a speed of 17 knots (a) Determine the frictional energy absorbed by the breaks (b) Consider that the stopping force is brought by a constant collinear force resisting the motion, what is the force? Note: The kinetic energy of rotation of the wheel is negligible Given: m 170 lbs M-757 kg
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- A 7.80-g bullet moving at 600 m/s penetrates a tree trunk to a depth of 4.80 cm. (a) Use work and energy considerations to find the average frictional force that stops the bullet.N(b) Assuming the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.3. A ball is falling and gains 20 J of kinetic energy. If air drag is also considered, does the ball-Earth system lose more than, less than, or equal to 20 J of potential energy? Explain using physical reasoning.A crane at a construction site lifts a concrete block with a mass of m = 482 kg from the ground to the top of a building with a height of h = 23.9 m. How much work did the motor of the crane do? (Assume zero energy loss in the lifting mechanism due to friction.) -112894 J moter If the duration of the lift was 1.35 minutes, then what was the average power performed by the crane?
- A bead of mass m sits on a frictionless helical wire whose shape is given by x = 4 cos(0), y = 4 sin(0), z = -50. After the bead is released from rest at z = 0 it slides down due to the gravitational force Fg = = -mg k. b) What is the energy before it is released? E = a) Denoting the speed of the bead as u, give the formula for the energy of this bead. E= * m V= Z=0 c) Give the speed of the bead when it has rotated about the z- axis n times: Here frictionless means that there is no loss of energy due to reaction forces or air resistance.A horizontal force of 150 N is applied to push a 40.0 kg box a distance 6.00 m on a rough horizontal surface. If the box moves quickly constant, determine: A. The work that reverses the 150 N force. B. The coefficient of kinetic friction between the box and the surface.A 2.35-kg object initially at rest has a gravitational potential energy of 74.6 J. Determine the speed of the object when it has moved under the influence of gravity to a location where its gravitational potential energy is 50.0 J. m/s
- A 2.30-kg object initially at rest has a gravitational potential energy of 74.0 J. Determine the speed of the object when it has moved under the influence of gravity to a location where its gravitational potential energy is 50.0 J. m/s1. A 23.0 kg child is playing on a swing with a length of 2.5 m. If the swing starts from rest and makes an angle of 40.0◦ with the vertical at the top of the swing, a) determine the child’s speed at the bottom of the swing neglecting friction. b) If the swing has a speed of 2.8 m/s at the bottom, determine the work done by friction during the downswing and, bonus) assuming the force of friction is constant, determine the maximum angle the swing attains on the upswing after passing through the bottom. Hint: Use the approximation that cos θ ≈ 1 − 1 2 θ 2 for angles given in radians.2 kg and M=3 kg, are connected by a very light string passing over a massless and frictionless pulley. The M block moves 3 m to the right with constant speed. A Two blocks of maSses M 147 %3D During this process, how much work is done on the M block by the tension in the string? (Take g= 10 m/s) %3D