*1-36. The tank containing gasoline has a long crack on its side that has an average opening of 10 um. The velocity through the crack is approximated by the equation u = 10(10°)[ 10(10“)y – y²] m/s, where y is in meters, measured upward from the bottom of the crack. Find the shear stress at the bottom, y = 0, and the location y within the crack where the shear stress in the gasoline is zero. Take Hy = 0.317(10-³) N•s/m².

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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*1-36. The tank containing gasoline has a long crack on its
side that has an average opening of 10 um. The velocity
through the crack is approximated by the equation
u = 10(10°) [ 10(1o-“)y – y²] m/s, where y is in meters,
measured upward from the bottom of the crack. Find the
shear stress at the bottom, y = 0, and the location y within
the crack where the shear stress in the gasoline is zero. Take
H3 = 0.317(103) N-s/m².
Transcribed Image Text:*1-36. The tank containing gasoline has a long crack on its side that has an average opening of 10 um. The velocity through the crack is approximated by the equation u = 10(10°) [ 10(1o-“)y – y²] m/s, where y is in meters, measured upward from the bottom of the crack. Find the shear stress at the bottom, y = 0, and the location y within the crack where the shear stress in the gasoline is zero. Take H3 = 0.317(103) N-s/m².
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