1 -31.10. The general solution of x' =-11-1х is3-3 -13(a) x = C1e-at-2+ C2 et | 3 | + C3 e* | 1-33(b) x = C et2+ C2e¬2t 0+ C3e-t33+ C2e-2t 13+ C3e-t(c) x = C, et-23-3(d) x = C1e-4t+ Cze-2t-3+ C3 e-31(e) None of the above.

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Answered: 1 -3 1. 10. The general solution of x'…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Explain the step by step process to get the final answer Problem #2: Differentiate f(x) = [(3x* – 5)(2x³ + 9x – 6)]° and solve f(2). Solution: Reason: +'(x) = - [(3x" - 5) ( 2 x³ + 9x - 6 3-1 = 3 C( 3x" - 5) ( ax³ + 9× - 6) ]* C( 3x4 -5) ( a x³ + 9x - 6) I 3C( 3x" - 5 ) + 9x - 6) j* C (3 x" - 5) d 9x -6) 4x -6) d ( 3x" -5) ] dx *P 3CL 3x" - 5) + 9 x - 6) ]* c <3 x" - 5 ) l6x* + 9) Lax3 + 9x -6) L12x3) f'
3) If g(x) = 2", and h(x) = 3x2 + x, find h(g(2)). (A) 20 (В) 28 (С) 6 (D) 52
I need an answer for number 6.
#14. Find what is missing with complete solution
49
3) F(x)= 2x - 4x° + 2x - 6
4. If f(x) = ax² + bx + c, and f (x − 1) = f (x) + x + 1, what is the value of (a + b)? (A) (B) (C) (D) 3 (E) Solve yourself: 2 1 - نیا انا لنا ما 3 4 Substitute x=0 into first equation: (A) 11 (B) 19 (C) 29 (D) 39 (E) 41 Solve yourself: f(0) = c Substitute x-1 into first equation: f(1) = a(1)^2 + b(1) + c f(1) =a+b+c { Substitute x=0 into second equation: f(0 + 1) = : 5. If f(x) = x² + 3 and g(x) = 3f(x), what is the greatest possible value of f (x - 1), if g (x) = 84?
If i =1, where i =\-1 , then which of the following is a solution for x? (1) x=5 (3) x=7 (2) x = 6 (4) x= 8
If d (a) = 5, 3, h (x) = 2a2- 5x +7, k (a) = V2x -6. f () = a-1, g (2) = 2z - 2x+8) Find (g - f) (x)
#14
2x 5х-3 + 3x 12 2. 4x2 – 16 > 0 (-0, 2], [2, c∞0)
can you please explain how they got this answer

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1 -3 1. 10. The general solution of x' = -1 1 -1 |х is 3 -3 -1 3 (a) x = Ce-t -2 + C2e*| 3+ C3e* | 1 -3 3 (b) x = Cet 2 + C2e-2t| 0 + C3e-t -3 1 3 3 + C2e-2t| 1 + C3e-t 3 (c) x = C, et -2 3 1 -3 (d) x = C1e¬t 2 + C2e-2t -3 |+ C3 e -3 (e) None of the above.

1 -3 1. 10. The general solution of x' = -1 1 -1 |х is 3 -3 -1 3 (a) x = Ce-t -2 + C2e| 3+ C3e | 1 -3 3 (b) x = Cet 2 + C2e-2t| 0 + C3e-t -3 1 3 3 + C2e-2t| 1 + C3e-t 3 (c) x = C, et -2 3 1 -3 (d) x = C1e¬t 2 + C2e-2t -3 |+ C3 e -3 (e) None of the above.