23.6.10111213 1415 16 17181A2A3A 4A SA 6A TASAHe1.0084.0039.3.9.10LIBeNe6.941 9.01210.81 12.01 14.01 16.00 19.00 20.181112131415161718NaMgAlSiAr22.99 24.312698 28 09 30 97 32.07354539.95192021293233343622Se232425262728303135KCaTiCrFeCeNICuZaGaGeAsSe BrKr39.10 40 0s 44.96 47 $8 50.94 52 00 54.94 55 83 38.93 58 69 63.55 65 38 69 7272 59 7492 78 9679 90 83.8045Rh Pd$5.47 87.62]SS 91|91 22192.9195 94 (98) 101.11029106.4 107.9112 4114 SIIS.7121.S127.6126 9 13137737383940414243444647484950$1525354RbSrZrNbMoTeRuAg CaInSaSbTeXe$586$182TI757678798083845657La55727374CsBaTaWRe OuIrPtAuHePbBiPoAtRn132 91373 138 9|178.51So 9183 91862190 2|192 2195 1197 0/200.6 204 42072209.0209)210222)87SS89AcRa(223) 226 227)FrCalculate the pH of a 50.00 mL of 0.2000 M ammonia (Ka = 5.7 x 10-10) solution after addition of 50.00 mLof 0.2000 MI HCl in the titration.1. O5.772. 04.883. O5.034. 05.275. 05.12nny

Answered: Image /qna-images/answer/78d44e9e-1f53-4172-982f-f0e59f87b2f2.jpg

1 2 4. 10 11 12 13 14 15 16 17 18 1A 2A 3A 4A SA 6A TA BA He 1.008 4.003 4. 9. 6. 10 Li Be B. 10.81 12.01 14.01 16.00 19.00 20.18 F Ne 6.941 9.012 11 12 13 14 15 16 17 18 Na Mg 22.99 2431 Al Si Ar 26 98 28 09 3097 32.07 35.4539.95 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 Se Ce 39 10 40 0S 44 96 47 SS 50.94 52 00 5494 55 83 58.9358 69 63 55 65 38 69 7272 59 7492 78 96 79 90 83.80 45 K Ca Se Ti Cr Mn Fe NI Cu Za Ga Ge As Br Kr 37 3\ 39 40 41 42 43 44 46 47 48 49 50 51 52 53 54 Rb Sr Zr Nb Mo Te Ru Rh Pd Ag In S Sb Te Xe $5.47 87 62| SS 91|91 221929195 94 (98) 101.1102 9106 4 107.91124114SIIS.7121S 1276126 9131 3 86 Rn 75 76 77 78 79 80 81 82 83 84 $5 56 57 La 55 72 73 74 Cs Ba Ta W Re Os Ir Pt Au Hg TI Pb Bi Po At 132 9 1373 138 9178.51so 9183 91862190 2|192 2195 1197 o/200.6 204 4207 2209.0l209210222) 87 SS 89 Fr (223 226 227) Ra Ac Calculate the pH of a 50.00 mL of 0.2000 M ammonia (Ka = 5.7 x 10-10) solution after addition of 50.00 mL of 0.2000 MI HCl in the titration. 1. O5.77 2. 04.88 3. O5.03 4. 0527 5. 05.12

1 2 4. 10 11 12 13 14 15 16 17 18 1A 2A 3A 4A SA 6A TA BA He 1.008 4.003 4. 9. 6. 10 Li Be B. 10.81 12.01 14.01 16.00 19.00 20.18 F Ne 6.941 9.012 11 12 13 14 15 16 17 18 Na Mg 22.99 2431 Al Si Ar 26 98 28 09 3097 32.07 35.4539.95 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 Se Ce 39 10 40 0S 44 96 47 SS 50.94 52 00 5494 55 83 58.9358 69 63 55 65 38 69 7272 59 7492 78 96 79 90 83.80 45 K Ca Se Ti Cr Mn Fe NI Cu Za Ga Ge As Br Kr 37 3\ 39 40 41 42 43 44 46 47 48 49 50 51 52 53 54 Rb Sr Zr Nb Mo Te Ru Rh Pd Ag In S Sb Te Xe $5.47 87 62| SS 91|91 221929195 94 (98) 101.1102 9106 4 107.91124114SIIS.7121S 1276126 9131 3 86 Rn 75 76 77 78 79 80 81 82 83 84 $5 56 57 La 55 72 73 74 Cs Ba Ta W Re Os Ir Pt Au Hg TI Pb Bi Po At 132 9 1373 138 9178.51so 9183 91862190 2|192 2195 1197 o/200.6 204 4207 2209.0l209210222) 87 SS 89 Fr (223 226 227) Ra Ac Calculate the pH of a 50.00 mL of 0.2000 M ammonia (Ka = 5.7 x 10-10) solution after addition of 50.00 mL of 0.2000 MI HCl in the titration. 1. O5.77 2. 04.88 3. O5.03 4. 0527 5. 05.12

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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