1A 2A3A 4A SA 6A 7ASA2He1.0083LiBe6.9419.0124.00310Ne10.81 12.01 14.01 16.00 19.00 20.1sBC114 15Si1213161718s aNa Mg22.99 24 3119AlAr26.98 28 09 30 9732.073545 39 9s29 30 31Ce Za202122 232425Cr Ma26 27 283233 343536Se BrKCaSeTIFeCoNIGa GeAsKr39 10 40.0s 44 9647 ss so 94 52.00 54.94 5s.s5 ss 93 58 6963 5565 35 69 7272 59 7492 78 96 79 90 83.s0373839404142434445Rh4647484950Sa5152Te I354XeSrZrNb MoTeRuPd Ag CdIn$547 8762 88.9191 22 92.9195 94 (95) 10111029106.4 10791124114 811871218 1276126.9 131378 797677OsIr Prso S1As Hg$2 $35556 37Ba La H Ta W72 73 747584$5$6Bi PoAt RaReTIPb1329|1373138 o178 5180 9|183.9|186 2190 2|192.2|195.1|1970/200.6 204.4|207 2|209.0l209 210)l222)SS 19Fr Ra Ae87(223) 226 227)Question 11 / 12ميز هذا السؤالGiven the reaction below, how many grams of KI are needed to produce 3.0 g of the yellow solid PbI2. 2KI + Pb(NO3)2-Pbl2 (s) + 2KNO31. 00.722. 02.163. 00.544. 01.44

Potassium iodide reacts with lead nitrate to give lead iodide along with potassium nitrate.

Question 11/ 12 ميز هذا السؤال Given the reaction below, how many grams of KI are needed to produce 3.0 g of the yellow solid Pbl2. 2KI + Pb(NO3) 2-Pbl2 (s) + 2KNO3 1. 00.72 2. 02.16 3. 00.54 4. 01.44

Question 11/ 12 ميز هذا السؤال Given the reaction below, how many grams of KI are needed to produce 3.0 g of the yellow solid Pbl2. 2KI + Pb(NO3) 2-Pbl2 (s) + 2KNO3 1. 00.72 2. 02.16 3. 00.54 4. 01.44

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

1A 2A
3A 4A SA 6A 7A
SA
2
He
1.008
3
Li
Be
6.9419.012
4.003
10
Ne
10.81 12.01 14.01 16.00 19.00 20.1s
BC
1
14 15
Si
12
13
16
17
18
s a
Na Mg
22.99 24 31
19
Al
Ar
26.98 28 09 30 9732.073545 39 9s
29 30 31
Ce Za
20
21
22 23
24
25
Cr Ma
26 27 28
32
33 34
35
36
Se Br
K
Ca
Se
TI
Fe
Co
NI
Ga Ge
As
Kr
39 10 40.0s 44 9647 ss so 94 52.00 54.94 5s.s5 ss 93 58 6963 5565 35 69 7272 59 7492 78 96 79 90 83.s0
37
38
39
40
41
42
43
44
45
Rh
46
47
48
49
50
Sa
51
52
Te I
3
54
Xe
Sr
Zr
Nb Mo
Te
Ru
Pd Ag Cd
In
$547 8762 88.9191 22 92.9195 94 (95) 10111029106.4 10791124114 811871218 1276126.9 1313
78 79
76
77
Os
Ir Pr
so S1
As Hg
$2 $3
55
56 37
Ba La H Ta W
72 73 74
75
84
$5
$6
Bi Po
At Ra
Re
TI
Pb
1329|1373138 o178 5180 9|183.9|186 2190 2|192.2|195.1|1970/200.6 204.4|207 2|209.0l209 210)l222)
SS 19
Fr Ra Ae
87
(223) 226 227)
Question 11 / 12
ميز هذا السؤال
Given the reaction below, how many grams of KI are needed to produce 3.0 g of the yellow solid PbI2. 2KI + Pb(NO3)
2-Pbl2 (s) + 2KNO3
1. 00.72
2. 02.16
3. 00.54
4. 01.44

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