1-1 Determine the resultant internal normal force acting on the cross section through point A in each column. In (a), segment BC weighs 180 lb/ft and segment CD weighs 250 lb/ft. In (b), the column has a mass of 200 kg/m. 10 ft 4 ft 8 in. 4 ft 5 kip B 3 kip 3 kip 8 in. A D 200 mm 6 kN 200 mm 4.5 kN (a) FA=13-8 Prob. 1-1 18 kN 200 mm 6 kN 3 m 200 mm 4.5 kN Im (b) FA = 349

1-1 Determine the resultant internal normal force acting on the cross section through point A in each column. In (a), segment BC weighs 180 lb/ft and segment CD weighs 250 lb/ft. In (b), the column has a mass of 200 kg/m. 10 ft 4 ft 8 in. 4 ft 5 kip B 3 kip 3 kip 8 in. A D 200 mm 6 kN 200 mm 4.5 kN (a) FA=13-8 Prob. 1-1 18 kN 200 mm 6 kN 3 m 200 mm 4.5 kN Im (b) FA = 349

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Members with compression and bending

Compression members are structural elements that carry compressive axial force. They are the vertical members of a building that support beams and their design, which is governed by buckling and strength. Columns are known as struct or compression members, which are subjected to compressive forces. These members provide stiffness to the building and avoid any imperfection regarding the transfer of axial load. For instance, webs in a truss, braces in a framed structure, tiers, and so on.

Question

1-1 Determine the resultant internal normal force acting
on the cross section through point A in each column. In (a),
segment BC weighs 180 lb/ft and segment CD weighs
250 lb/ft. In (b), the column has a mass of 200 kg/m.
10 ft
4 ft
8 in.
4 ft
5 kip
B
3 kip 3 kip
8 in.
A
D
200 mm
6 kN
200 mm
4.5 kN
(a)
FA=13-8 Prob. 1-1
18 kN
200 mm
6 kN
3 m
200 mm
4.5 kN
Im
(b)
FA = 349

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