1 0 -2 has a single real eigenvalue A =-3 with algebraic multiplicity three. (a) Find a basis for the associated eigenspace. The matrix A= 0 8 -3 0 0 Basis - (b) is the matrix A defective? DA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity OB. A is not defective because the eigenvalue has algebraic multiplicity three Oc. A is defective because it has only one eigenvalue OD. A is not defective because the eigenvectors are linearly independent

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