04a. The winding on the steel core has 300 turns and the current passes through the winding is 200 mA. Mean path length P= 500 mm I= 200 mA N= 300 turns Cross-seetional area -25 mm * 25 mm Figure Q4a Given the permeability of free space lo = 4x x 10" T/(At/m) and the relative permeability of steel, u.= 800, determine: (i) the magnetomotive force (MMF) produced by the coil; the magnetic field strength (H) in the coil; (ii) (iii) the average magnetic flux density (B): (iv) the magnetic flux (). (b) Ajn inductance circjit is shown in Figure Q4b. The total current flow in the circuit is 2A. IT = 2A LI -4 H L3 = 20 H a o ele LT L2 = 7 H L4 = 12 H bo m L5 = 10 H elll L6-8 H Figure Q4b Determine: (i) the total inductance (L) of the circuit; (ii) the total energy stored in the circuit.
04a. The winding on the steel core has 300 turns and the current passes through the winding is 200 mA. Mean path length P= 500 mm I= 200 mA N= 300 turns Cross-seetional area -25 mm * 25 mm Figure Q4a Given the permeability of free space lo = 4x x 10" T/(At/m) and the relative permeability of steel, u.= 800, determine: (i) the magnetomotive force (MMF) produced by the coil; the magnetic field strength (H) in the coil; (ii) (iii) the average magnetic flux density (B): (iv) the magnetic flux (). (b) Ajn inductance circjit is shown in Figure Q4b. The total current flow in the circuit is 2A. IT = 2A LI -4 H L3 = 20 H a o ele LT L2 = 7 H L4 = 12 H bo m L5 = 10 H elll L6-8 H Figure Q4b Determine: (i) the total inductance (L) of the circuit; (ii) the total energy stored in the circuit.
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images