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000A ... 6.30 Consider two wires parallel to each other, as in Figure P.6.3, of the same length L, of different currents ii and i2, and separated by a distance d. Using Eqs. (6.15), (6.26), and (6.27), show that these wires exert a force on each other of magnitude Ho ii2L F = (6.127) 27 d Using the right-hand-rules for the magnetic force and the magnetic field of a current-carrying wire, explain why this force is attractive for parallel currents and repulsive for antiparallel currents26.

000A ... 6.30 Consider two wires parallel to each other, as in Figure P.6.3, of the same length L, of different currents ii and i2, and separated by a distance d. Using Eqs. (6.15), (6.26), and (6.27), show that these wires exert a force on each other of magnitude Ho ii2L F = (6.127) 27 d Using the right-hand-rules for the magnetic force and the magnetic field of a current-carrying wire, explain why this force is attractive for parallel currents and repulsive for antiparallel currents26.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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6.33 In Figure P.6.4, VB = 12.0 V, R1 = 100.0 N, R2 = 55.0 N, R3 = 75.0 N, concentric (i.e., same-center) cylinders. If a current of 55.0 mA is placed through 80 turns. You place the 5.0-cm coil inside the 12.0-cm coil, such that they form the outer coil, how much current must be created in the inner coil such that the RONICS 283 6.10. PROBLEMS TARD ... 6.30 Consider two wires parallel to each other, as in Figure P.6.3, of the same length L, of different currents i and i2, and separated by a distance d. Using Eqs. (6.15), (6.26), and (6.27), show that these wires exert a force on each other of magnitude Ho ii2 L 27 d F = (6.127) Using the right-hand-rules for the magnetic force and the magnetic field of a current-carrying wire, explain why this force is attractive for parallel currents and repulsive for antiparallel currents26. * 6.31 What current is required to create a magnetic field of 1.00 T in a 100-turn solenoid of length 5.0 m with air (K, 1) in the center? .. 6.32 You have two coils of wire; the first has a radius of 12.0 cm, a lenøơth of 1.0 m, and 50 turns: the second has a radius of 5.0 cm, a length of 1.0 m and magnetic field at the center of the inner coil is zero? R1 R2 VB R4 6.4. Figur ch resistor? urr and R4 = 15.0 O hau
Transcribed Image Text:6.33 In Figure P.6.4, VB = 12.0 V, R1 = 100.0 N, R2 = 55.0 N, R3 = 75.0 N, concentric (i.e., same-center) cylinders. If a current of 55.0 mA is placed through 80 turns. You place the 5.0-cm coil inside the 12.0-cm coil, such that they form the outer coil, how much current must be created in the inner coil such that the RONICS 283 6.10. PROBLEMS TARD ... 6.30 Consider two wires parallel to each other, as in Figure P.6.3, of the same length L, of different currents i and i2, and separated by a distance d. Using Eqs. (6.15), (6.26), and (6.27), show that these wires exert a force on each other of magnitude Ho ii2 L 27 d F = (6.127) Using the right-hand-rules for the magnetic force and the magnetic field of a current-carrying wire, explain why this force is attractive for parallel currents and repulsive for antiparallel currents26. * 6.31 What current is required to create a magnetic field of 1.00 T in a 100-turn solenoid of length 5.0 m with air (K, 1) in the center? .. 6.32 You have two coils of wire; the first has a radius of 12.0 cm, a lenøơth of 1.0 m, and 50 turns: the second has a radius of 5.0 cm, a length of 1.0 m and magnetic field at the center of the inner coil is zero? R1 R2 VB R4 6.4. Figur ch resistor? urr and R4 = 15.0 O hau
Figure P.6.3. Figure for Problem 4.30. Figure P.6.2. Figure for Problem 4,28 wire 2 wire 1 and d of 50 6. and .. 6.3 26 Ca
Transcribed Image Text:Figure P.6.3. Figure for Problem 4.30. Figure P.6.2. Figure for Problem 4,28 wire 2 wire 1 and d of 50 6. and .. 6.3 26 Ca
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