25. A coaxial cable consists of a solid inner cylindrical conductor of radius 2 mm and an outer cylindrical shell of inner radius 3 mm and outer radius 3.5 mm. A current of 15 A flows down the inner wire and an equal return current flows in the outer conductor. If we assume that the currents are uniform over the cross section of the conductors, then calculate the magnitude of the enclosed current for use in Ampere's Law at a radius of 3.25 mm. a. 7.2 A b. C. d. e. 3.8 A 7.8 A 11.2 A 7.5 A

25. A coaxial cable consists of a solid inner cylindrical conductor of radius 2 mm and an outer cylindrical shell of inner radius 3 mm and outer radius 3.5 mm. A current of 15 A flows down the inner wire and an equal return current flows in the outer conductor. If we assume that the currents are uniform over the cross section of the conductors, then calculate the magnitude of the enclosed current for use in Ampere's Law at a radius of 3.25 mm. a. 7.2 A b. C. d. e. 3.8 A 7.8 A 11.2 A 7.5 A

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

25. A coaxial cable consists of a solid inner cylindrical conductor of radius 2 mm and an outer
cylindrical shell of inner radius 3 mm and outer radius 3.5 mm. A current of 15 A flows down the
inner wire and an equal return current flows in the outer conductor. If we assume that the currents are
uniform over the cross section of the conductors, then calculate the magnitude of the enclosed
current for use in Ampere's Law at a radius of 3.25 mm.
7.2 A
a.
b.
C.
d.
e.
3.8 A
7.8 A
11.2 A
7.5 A

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