門 ·0225mLx.1M = 2,25 × 10-3 mol NaOH 1.125 x 103 mul Acid A 1125×15 IL A Q 68 D D * AS AS SUFF ASUN! + -01125M + yel + 129 molar any) = mots Acit st ·0/125201 = (.129 Nolar Nars 16 F + > 17-1.44 4 १५.०५५ 1.125×103 = -3 125 molar ma Molar Mass = 106 g/md pure, ubstances mixed AST, V,i- A 4x² I 2 ,ok o D 4(096) ~ksp C +25 2, (ok) 2n + гон x (2x+) = 111 I (ol both) (0/60+23] 4080-11 0 X 00101 25 (0080+5)/45) = 3.00 × 10 17 (0.032,4,2) 4.0725 5.2851×150 5.78645×105 2-1773210-4 2.732x157 (.01901(42) (.0020) (4)
門 ·0225mLx.1M = 2,25 × 10-3 mol NaOH 1.125 x 103 mul Acid A 1125×15 IL A Q 68 D D * AS AS SUFF ASUN! + -01125M + yel + 129 molar any) = mots Acit st ·0/125201 = (.129 Nolar Nars 16 F + > 17-1.44 4 १५.०५५ 1.125×103 = -3 125 molar ma Molar Mass = 106 g/md pure, ubstances mixed AST, V,i- A 4x² I 2 ,ok o D 4(096) ~ksp C +25 2, (ok) 2n + гон x (2x+) = 111 I (ol both) (0/60+23] 4080-11 0 X 00101 25 (0080+5)/45) = 3.00 × 10 17 (0.032,4,2) 4.0725 5.2851×150 5.78645×105 2-1773210-4 2.732x157 (.01901(42) (.0020) (4)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hello I need help clarifying how this person got a molar mass 106 g/mol. The image shows the how person got the answer, I am just still confused.
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