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1. Find the number of moles in 3.7 x 10 ^-5 g of magnesium phosphate

1. Find the number of moles in 3.7 x 10 ^-5 g of magnesium phosphate

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please answer this question correctly. dont just give an answer, please include brackets, mutiplucation ( if neccessary), etc.

1. Find the number of moles in 3.7 x 10 ^-5 g of magnesium phosphate.

 

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Mg,N, + 6 H,0 - 3 Mg|OH), + 2 NH, 51.8 g Ma (1 mol Mg,N, |101 gMg,N, Limiting reactant: In this reaction, we need six times mol Mg.N, as many moles of water as Ma,N, 0.513 and we have about half that many therefore HO is the limiting = 1.133 mol H,0 reactant. Now base all further work on 1.133 moles of H,0. 20.4 gH0/1 mol H,O 1.133 mat0 (3 mol-MgOH),58.3 g Mg(OH), 6 motHO 33.0 g Mg(OH), 1 mol-MgOH), 1.133 molo (2 mo-NH, 17 g NH, 6 moi,0||1mel-NH 6.42 g NH,
Transcribed Image Text:Mg,N, + 6 H,0 - 3 Mg|OH), + 2 NH, 51.8 g Ma (1 mol Mg,N, |101 gMg,N, Limiting reactant: In this reaction, we need six times mol Mg.N, as many moles of water as Ma,N, 0.513 and we have about half that many therefore HO is the limiting = 1.133 mol H,0 reactant. Now base all further work on 1.133 moles of H,0. 20.4 gH0/1 mol H,O 1.133 mat0 (3 mol-MgOH),58.3 g Mg(OH), 6 motHO 33.0 g Mg(OH), 1 mol-MgOH), 1.133 molo (2 mo-NH, 17 g NH, 6 moi,0||1mel-NH 6.42 g NH,
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