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01 A 10 kVA, 500/2000 V, single-phase, 50 Hz transformer gave the following test results : 500 V at normal frequency applied to primary; power absorbed 120 W O.C. test S.C. test : 15 V at normal frequency applied to primary circulated full-load current in the short-circuited secondary; power absorbed 100 W Calculate (i) efficiency at full-load at unity p.f. (ii) secondary terminal voltage on F.L. at unity p.f., 0-8 lagging, 0-8 leading. [(i) 97-86 % (ii) 1980 V; 1950 V; 2018 VI

01 A 10 kVA, 500/2000 V, single-phase, 50 Hz transformer gave the following test results : 500 V at normal frequency applied to primary; power absorbed 120 W O.C. test S.C. test : 15 V at normal frequency applied to primary circulated full-load current in the short-circuited secondary; power absorbed 100 W Calculate (i) efficiency at full-load at unity p.f. (ii) secondary terminal voltage on F.L. at unity p.f., 0-8 lagging, 0-8 leading. [(i) 97-86 % (ii) 1980 V; 1950 V; 2018 VI

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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01 ; X01 = 0.31 2; 377-8 V A 10 kVA, 500/2000 V, single-phase, 50 Hz transformer gave the following test results : 500 V at normal frequency applied to primary; power absorbed 120 W O.C. test S.C. test : 15 V at normal frequency applied to primary circulated full-load current in the short-circuited secondary; power absorbed 100 W Calculate (i) efficiency at full-load at unity p.f. (ii) secondary terminal voltage on F.L. at unity p.f., 0-8 lagging, 0-8 leading. [(i) 97-86 % (ii) 1980 V; 1950 V; 2018 VI
Transcribed Image Text:01 ; X01 = 0.31 2; 377-8 V A 10 kVA, 500/2000 V, single-phase, 50 Hz transformer gave the following test results : 500 V at normal frequency applied to primary; power absorbed 120 W O.C. test S.C. test : 15 V at normal frequency applied to primary circulated full-load current in the short-circuited secondary; power absorbed 100 W Calculate (i) efficiency at full-load at unity p.f. (ii) secondary terminal voltage on F.L. at unity p.f., 0-8 lagging, 0-8 leading. [(i) 97-86 % (ii) 1980 V; 1950 V; 2018 VI
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